3 years ago

"The quotient of a number and 5" is the same as.

Mathematics

1 answer:

MatroZZZ [7]3 years ago

4 0

N/5 hope this helps :)

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From the airport hanger H, an areoplane A is 18km away on the bearing of 115° while another aeroplane B is 29km away on a bearin

maks197457 [2]

The difference in distance between Aero plane A and B is; 34.67 km

<h3>How to calculate bearing?</h3>

To get the bearing;

∠H = (115 - 90) + (270 - 203)

∠H = 92°

Then, we will use cosine rule to get the distance between both Planes A and B.

d_ab = √(18² + 29² - 2(18 * 29) * cos 92)

d_ab = √(324 + 841 + 36.435)

d_ab = 34.67 km

Read more about bearing at; brainly.com/question/22518031

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2 years ago

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3 years ago

Does 12-(4x2)=(12-4)x(12-2)

Darina [25.2K]

No. Solve each of the problems and see if they match. Do PEMDAS order of operations

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3 years ago

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Find the value of x. Show your work.

atroni [7]

Answer:

Step-by-step explanation:

x+(x+70)+28=180

x+x+70+28=180

2x+70+28=180

2x+98=180

2x=180-98

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x=82/2

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3 years ago

Find the Total Surface area of a Pyramid. Its base is a regular hexagon 4cm on a side. its height is 8 cm. Round off to nearest

oksano4ka [1.4K]

Answer:

The total surface area of a regular hexagonal pyramid is 146.2 cm².

Step-by-step explanation:

The base is a regular hexagon 4cm on a side. its height is 8 cm.

The total surface area of a pyramid with regular hexagon base

$A=\frac{3\sqrt{3}}{2}a^2+3a\sqrt{h^2+\frac{3a^2}{4}$

Where, a represents the base edge and h represents the height of the pyramid.

The area of given regular hexagonal pyramid is

$A=\frac{3\sqrt{3}}{2}(4)^2+3(4)\sqrt{(8)^2+\frac{3(4)^2}{4}$

$A=\frac{3\sqrt{3}}{2}(16)+12\sqrt{64+12}$

$A=24\sqrt{3}+12\sqrt{76}$

$A=146.182794027$

$A=146.2$

The total surface area of a regular hexagonal pyramid is 146.2 cm².

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3 years ago