For #4, break up what's under the radical sign into 100 * 2, and then break the n^8 into n^2*n^2*n^2*n^2 so it's easy to see how to pull out what you need to. 100 is a perfect square: 10*10, so you can pull that out, leaving the 2, and you can also pull out 4 n's, so for #4, the answer is 10n^4 sqrt2.
#5 breaks up into 9*7, with 9 being the perfect square 3*3. Break the n^9 up into n^2*n^2*n^2*n^2*n. So you can pull out the 3 and 4 of the n's, which gives you 3n^4sqrt7n
Answer:
With 20 visits in one year the cost of the clulbs are equal.
Step-by-step explanation:
On the club A the amount paid in function of the number of visits can be expressed as bellow:
cost = 60 + 2*visits
On the club B the amount paid in function of the number of visits can be expressed as:
cost = 20 + 4*visits
In order for the cost to be the same we must find a value of visits that makes them equal, so we have:
60 + 2*visits = 20 + 4*visits
2*visits - 4*visits = 20 - 60
-2*visits = -40
visits = 20
With 20 visits in one year the cost of the clulbs are equal.
Step-by-step explanation:
<u>Given </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Slope</u><u> intercept</u><u> form</u><u> </u><u>:</u><u>-</u><u> </u>
→ 4x + 3y - 8 = 0
→ 3y = -4x + 8
→ y = (-4x + 8)/3
→ y = -4/3x + 8/3
7.1(10) = 71 <== 10 times greater means multiply
