The quotient of 20 and four, multiplied by 10 as an expression

Octavio Harvey wants the photocopy of a document that measures 6 centimeters by 9 centimeters enlarged by a factor of 3.

VLD [36.1K]

B is your answer have a nice day and sorry it took this long to get an answer :)

4 0

3 years ago

Reflect 4, 1 in the x-axis

Marysya12 [62]

Hello there,

When you reflect a point over the x-axis the x-coordinate stays the same while the y-coordinate is its opposite.

In the given point (4,1) when it is reflected over the x-axis you would get (4, -1).

Hope I helped,

Amna

8 0

2 years ago

An automobile club reported that the average price of regular gasoline in a certain state was $2.61 per gallon. The following d

laila [671]

Answer:

$2.618-2.98\frac{0.078}{\sqrt{15}}=2.56$

$2.618+2.98\frac{0.078}{\sqrt{15}}=2.68$

So on this case the 99% confidence interval would be given by (2.56;2.68)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=2.618$

The sample deviation calculated $s=0.078$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$

Now we have everything in order to replace into formula (1):

$2.618-2.98\frac{0.078}{\sqrt{15}}=2.56$

$2.618+2.98\frac{0.078}{\sqrt{15}}=2.68$

So on this case the 99% confidence interval would be given by (2.56;2.68)

5 0

3 years ago

Laura is putting her dog on a diet.

Vera_Pavlovna [14]

Answer:

it would take 12 months

Step-by-step explanation:

is she currently weighs 110 pounds and u want her to get to 80 then we have to subtract 110-80 which equals 30 and since she loses 2.5 pounds per month then we have to divide 30/2.5 which makes 12 so now ur answer is 12MONTHS

6 0

3 years ago

i am aware that this question uses second ftc, however, i keep getting the wrong answer. any guidance is appreciated.

Gnesinka [82]

Answer:

C. 14

Step-by-step explanation:

F(x) = ∫₀²ˣ √(t³−15) dt

Use second fundamental theorem of calculus:

F'(x) = √((2x)³−15) d/dx (2x)

F'(x) = 2 √(8x³−15)

Evaluate at x=2:

F'(2) = 2 √(8×2³−15)

F'(2) = 2 √(64−15)

F'(2) = 2 √49

F'(2) = 14

7 0

3 years ago