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3 years ago

If cos28 = x/4, find x(3sf)

1 answer:

3 0

Cos28 = x/4 so to get rid of the fraction , multiply each side by 4 so it'll be
4cos28 = x
x = 3.531790371
Hope this helps=)

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How do I solve this?

mart [117]

X + y = 20 Substitute
x by 2 y - 4 in x + y = 20 to obtain 2 y •
4 + y = 20 Solve for y to find y = 8 and
x = 2y - 4 = 12

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2 years ago

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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 18 N acts on

inysia [295]

Answer: $F=15N$

Step-by-step explanation:

1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:

$F=ka$

Where $F$ is the force acting on the object, $a$ is the object's acceleration and $k$ is the constant of proportionality.

2. Keeping this on mind, you can calculate the constant of proportionality by substituting $F=18$ and $a=6$ into the equation and solving for $k$ :

$18=k6\\k=\frac{18}{6}\\k=3$

3. Now, you can calculate the force when the acceleration of the object becomes 5 m/s², as following:

$F=3(5)\\F=15$

3. The result is:

$F=15N$

7 0

3 years ago

What is the opposite of the opposite of -2

melisa1 [442]

Answer:

2 is the opposite of-2 and -2 is the opposite of 2

3 0

2 years ago

-2(u+3)-5u<br><br> use distributive property to simplify

gayaneshka [121]

The answer is
-2(u+3)-5u
-2u-6-5u
-3u-6

3 0

2 years ago

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Use the definition of a derivative to find f’(x).

tatyana61 [14]

Answer:

f'(x) = $-\frac{9}{x^2}$

Step-by-step explanation:

i) f(x) = 9 / x

ii) f'(x) = $$\lim_{h\to 0} \frac{f(x+h) - f(x)}{h} $ \hspace{0.2cm}$

$= $\lim_{h\to 0} \frac{\frac{9}{x+h} - \frac{9}{x} }{h} = \hspace{0.1cm} $\lim_{h\to 0} \frac{9x - 9(x+h)}{hx(x+h)} $ \hspace{0.1cm} = \hspace{0.1cm}$\lim_{h\to 0} \frac{-9h}{hx(x+h)} = $\lim_{h\to 0} \frac{-h}{x(x+h)} = \frac{-9}{x^2}$$

7 0

3 years ago