Answer:
(a) Equation:
(b) 7.5 gallons
Step-by-step explanation:
Given
Current Gas = 10 gallon
Every Hour = -1.25 gallon
Solving for (a): An equation for the scenario
This question represents an Arithmetic Progression and will be solved using the following formula:
Where
Substitute these values in the formula
Collect Like Terms
Solving for (b): In this case, n - 3
Substitute 3 for n in
<em>7.5 gallon of gas left</em>
Step-by-step explanation:
just to fit characters ...........
Answer:
The product between 22 and p.
Another way would be : 22 times p.
Step-by-step explanation:
One way to write 22p would be:
The product between 22 and p.
Another way would be : 22 times p.
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Answer:
Step-by-step explanation:
With a factor of (t - 1) we know that zero (ground level) is reached at 1 second from an initial height of (0 - 1)(0 - 1)(0 - 11)(0 - 13)/3 = -1•-1•-11•-13 / 3 = 47⅔ meters at t = 0
As we have <em>two </em>factors of (t - 1) we know the track does not go underground at t = 1, but rises again.
At t = 11 seconds, the car has again returned to ground level, but as we only have a single factor of (t - 11) the car plunges below ground level and returns to above ground level at t = 13 seconds due to the single factor of (t - 13)
we can estimate that the car is the deepest below ground level halfway between 11 and 13 s, so at t = 12. At that time, the depth will be about (12 - 1)(12 - 1)(12 - 11)(12 - 13) / 3 = -(11²/3) = - 40⅓ m.
we can estimate that the car is the highest above ground level halfway between 1 and 11 s, so at t = 6s. At that time, the height will be about (6 - 1)(6 - 1)(6 - 11)(6 - 13) / 3 = 5²•-5•-7 / 3 = 291⅔ m.
It's obvious that the roller coaster car had significant initial velocity at t = 0 to achieve that altitude from an initial height of 47⅔ m
Step-by-step explanation:
If two triangles are congruent, then each part of the triangle (side or angle) is congruent to the corresponding part in the other triangle. This is the true value of the concept; once you have proved two triangles are congruent, you can find the angles or sides of one of them from the other.