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Ede4ka [16]
3 years ago
8

Sam packed 42 kg of rice into one big bag and six small ones which were of the same size the small bags .each contain 1/10 of th

e rice .how many kilograms of rice did the big bag contain?
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

we are given

Sam packed 42 kg of rice

So, total amount of rice =42kg

And there are six small bags

each contains 1/10 of the rice

So, rice on each bags is

=\frac{1}{10}\times 42

=4.2kg

so, total rice in 6 bags is

=6\times 4.2kg

=25.2kg

so, the rice in big bag = ( total amount of rice )-( total rice in six small bags)

we can plug values

and we get

so, the rice in big bag is

=42-25.2

=16.8kg..............Answer

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So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
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We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
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Substitute again.
x = 2(86 \frac{2}{3} )-20

Multiply.
x = 173 \frac{1}{3} -20

Subtract.
Joe's\ weight = 153 \frac{1}{3}\ lbs.

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.
Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.
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