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4 years ago

What is the midpoint of OA

Mathematics

2 answers:

Anna007 [38]4 years ago

5 0

Answer:

Step-by-step explanation:

if i had to guess i would say a

sattari [20]4 years ago

4 0

ANSWER

The midpoint is a) (m,n)

EXPLANATION

The point O has coordinate (0,0) and the point A has coordinate (2m,2n)

The x-coordinate of the midpoint is

$x = \frac{0 + 2m}{2}$

$x = \frac{2m}{2}$

$x = m$

Also,

$y = \frac{0 + 2n}{2}$

$y = \frac{ 2n}{2}$

$y = n$

The answer is A

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Step-by-step explanation:

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The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

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(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

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