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DENIUS [597]
3 years ago
8

What is the midpoint of OA

Mathematics
2 answers:
Anna007 [38]3 years ago
5 0

Answer:

Step-by-step explanation:

if i had to guess i would say a

sattari [20]3 years ago
4 0

ANSWER

The midpoint is a) (m,n)

EXPLANATION

The point O has coordinate (0,0) and the point A has coordinate (2m,2n)

The x-coordinate of the midpoint is

x =  \frac{0 + 2m}{2}

x =  \frac{2m}{2}

x = m

Also,

y =  \frac{0 + 2n}{2}

y =  \frac{ 2n}{2}

y = n

The answer is A

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Please help, Thanks.
Evgen [1.6K]

Answer:

C

Step-by-step explanation:

49x² + 28xy + 4y² ← is a perfect square of the form

(ax + by)² = a²x² + 2abxy + b²y²

49 = 7² ⇒ a = 7 and 4 = 2² ⇒ b = 2

2ab = 2 × 7 × 2 = 28

Hence

49x² + 28xy + 4y² = (7x + 2y)²

with factor 7x + 2y ⇒ C

8 0
3 years ago
In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D. z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

6 0
3 years ago
PLEASE HELP MEEE!!!!!
Natalka [10]

Answer:

what

Step-by-step explanation:

why would you even need to know this

4 0
2 years ago
What is the square root of 116
8090 [49]
It is 10.7703296143, but estimated it would be about 11. Hope I helped!! :)
4 0
3 years ago
Read 2 more answers
The length around the outside of semicircle O from point L through point M to point N is 14 centimeters. The perimeter of semici
Luden [163]
The area would be 83.67 cm.

A semicircle is half of a circle.  The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle.  The formula for circumference is:

C=πd

Using our information, we have  

22.92 = 0.5(3.14)d
22.92 = 1.57d

Divide both sides by 1.57:

22.92/1.57 = 1.57d/1.57
14.6≈d

Since the diameter is 14.6, the radius is 14.6/2 = 7.3.

We use the radius for the area of the semicircle:

A=0.5πr²
=0.5(3.14)(7.3)²
=83.67
3 0
2 years ago
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