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3 years ago

9

how can you decide if finding common multiples and common factors is helpful in solving a problem?explain.

1 answer:

blondinia [14]3 years ago

7 0

You can evaluate all numbers and in the prosses, make any problem easier.

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11. A jug contains 2 gallons of water. How many quarts of water does the jug contain?

s2008m [1.1K]

Answer:

first change 1 gallon into quarts and that will be

4.8038

so 2 quarts = ? cross multiply ans the answer u will get is 9.6076

5 0

2 years ago

which of the following equations can be used to calculate the values of t for which the distance between Chris and any is 300 mi

Papessa [141]

The first thing we must know in this case is that the distance is equal to the speed for time.
We have then:
For Chris:
d1 = 40 * t
For Amy:
d2 = 60 * (t-2)
The distance between both will be given by the hypotenuse of the rectangle triangle:
300 = root ((40 * t) ^ 2 + (60 * (t-2)) ^ 2)
Answer:
300 = root ((40 * t) ^ 2 + (60 * (t-2)) ^ 2)
option 3

8 0

3 years ago

Read 2 more answers

Is 80 oz greater or less than 5 pounds

erastova [34]

80 oz and 5 lbs are the same

8 0

3 years ago

Read 2 more answers

We started with two and a half ounces of a perfume mix that was 96% alcohol. We added half an ounce of a preservative, and ended

Olenka [21]

Answer:

84%

Step-by-step explanation:

5 0

4 years ago

Polygon CCC has an area of 404040 square units. K 2ennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 1

nikdorinn [45]

Answer:

<em>Area of polygon D = 10 square units</em>

Step-by-step explanation:

<u>Given:</u>

Polygon <em>C </em>has an area of 40 square units.

It is scaled with a scale factor of $\frac{1}2$ to form a new polygon D.

<u></u>

<u>To find:</u>

The area of polygon D = ?

<u>Solution:</u>

When any polygon is scaled to half, then all the sides of new polygon are half of the original polygon.

And the area becomes one-fourth of the original polygon.

Let us consider this by taking examples:

First of all, let us consider a right angled triangle with sides <em>6, 8 and 10 units.</em>

Area of a right angled triangle is given by:

$A = \dfrac{1}{2} \times Base \times Height\\\Rightarrow A = \dfrac{1}{2} \times 6 \times 8 = 24\ sq\ units$

If scaled with a factor $\frac{1}{2}$ , the sides will be 3, 4 and 5.

New area, A':

$A' =\dfrac{1}{2} \times 3 \times 4 = 6\ sq\ units = \dfrac{1}4\times A$

i.e. Area becomes one fourth.

Let us consider a rectangle now.

Sides be 8 and 10 units.

Area of a rectangle, A = $Length \times Width$ = 8 $\times$ 10 = 80 sq units.

Now after scaling, the sides will be 4 and 5 units.

New Area, A' = 4 $\times$ 5 =20 sq units

So, $\bold{A' = \frac{1}4 \times A}$

Now, we can apply the same in the given question.

$\therefore$ Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ Area of polygon C

Area of polygon D = $\bold{\frac{1}{4}}$ $\times$ 40 = <em>10 sq units</em>

4 0

3 years ago