Question

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday.

Answer 1

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is $\frac{1}{6}$ which is on friday and then $\frac{1}{4}$ on monday.

Rest distance which is $\frac{6}{8}$ on wednesday.

Hence, Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Answer 2

Answer: The answers is Monday - one-fourth, Wednesday - six-eight and Friday - one-sixth.

Step-by-step explanation: Given in the question that Mason walked on Monday, Wednesday, and Friday with distances six-eights mile, one-fourth mile, and one-sixth mile. Also, he did not walk the farthest on Monday and he walked less on Friday than Monday. We are to find the distance he walk each day.

The ascending order of the distances travelled by Mason is

six-eights mile < one-fourth mile < one-sixth mile.

On Monday, Mason did not walk farthest and shortest, so Monday will be in the middle. Since Friday's distance is less than that of Monday, so Friday will be shortest and hence Wednesday will be farthest.

So, the days in ascending order are

Wednesday < Monday < Friday.

Thus, Monday - one-fourth, Wednesday - six-eight and Friday - one-sixth.