Answer:
Explanation:
Molar mass of C4H10 = 12x 4 + 1 x 10= 48+ 10=58g.
Also note that molar mass of a substance is equivalent to Avogadro's number (6.02 X 10^-23)
Hence,
6.02 X 10^-23 molecules of ethane was burned in 58g of ethane
So, 4.10 X 10^24 molecules of ethane will burn in xg of ethane.
Cross multiply:
6.02 X 10^-23x = 58 X 4.10 X 10^24
6.02 X 10^-23x = 2.378 X 10 ^26
Dividing both sides by the coefficient of 'x'
x = 2.378 X 10^26/(6.02X 10^-23)
x = 3.95 X10^48g approximately
x = 4.0 X 10^48g
Or
Mole = number of elementary
particless / Avogadro's number
Where,
No of elementary particles= 4.10 X 10^24 molecules
Avogadro's number= 6.02 x 10^-23
Therefore,
Mole = 4.10 X 10^24/ (6.02 X 10^-23)
= 6.81 X 10^ 46 moles.
But mole = mass / molar mass
Mass = mole x molar mass
where
Molar mass of C4H10 = 12x 4 + 1 x 10= 48+ 10=58g/mol
Mass= 6.81 X 10^46 X 58
= 3.95 X 10^48g approximately
= 4.0 X 10^ 48g.
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