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alina1380 [7]
3 years ago
12

When a liquid absorbs energy and changes to a gas, what takes place?

Chemistry
1 answer:
Anastasy [175]3 years ago
4 0
D, Evaporation. Like the water cycle..
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It is true/falseit that when hydrogen cyanide, h c n , dissolves in water, the solution is weakly conducting and acidic in natur
cluponka [151]
False is the correct answer.
8 0
3 years ago
What mass of benzene is cooled from 83.8 °C to 77.1 °C when 167 J of energy is transferred out of the system? (The specific heat
dexar [7]

Answer:

14.32g

Explanation:

Initial temperature = 83.8°C

Final temperature = 77.1°C

Temperature change, ΔT = 83.8°C - 77.1°C = 6.7

Heat, H = 167J

Specific heat, c = 1.740J/g °C

m = ?

All these parameters are related with the equation below;

H = mcΔT

m = H / cΔT

m = 167 /  (1.740 * 6.7)

m = 167 / 11.658 = 14.32g

3 0
4 years ago
A 25. 0-ml sample of 0. 150 m hydrocyanic acid is titrated with a 0. 150 m naoh solution. What is the ph beforeany base is added
Ray Of Light [21]

Answer:

stars,auroras,a neon sign

Explanation:

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4 0
3 years ago
If a gas is cooled from 325K to 275K and the volume is constant, what would the final pressure be if it was originally 750mmHg?
salantis [7]

Answer:

635

p/T is a constant

(750/325)×275

3 0
4 years ago
Calculate the values of ΔU, ΔH, and ΔS for the following process:
kykrilka [37]

The values of the changes are

ΔH = 46.44kJ

Δu =  43.34Kj

ΔS = 126.6 J/K

<h3>How to find change in H</h3>

= 1 mol + 75.3 (100 + 273) - 25 + 273 + 1 * 40.79

= 5.6475 + 40.79

= 46.44kJ

<h3>How to find change in S</h3>

1 mol + 75.3 x ln 373/298 + 1 mol x 40.79

= 0.1263

ΔS = 126.6 J/K

<h3>How to find the change in U</h3>

46.44 - 0.00831 * 373

= 43.34Kj

Read more on molar heat here:

brainly.com/question/13439286

#SPJ1

5 0
2 years ago
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