3 years ago

Find the simple interest on $500 at six percent for one year

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Answer: $30

Step-by-step explanation: The formula for simple interest is principal x rate x time.

Putting your numbers into the formula, it will look like this:

I = 500 x .06 x 1

I = 30 x 1

I = 30

The interest on $500 for one year is $30.

You might be interested in

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what i

swat32

Apply the Pythagoras Theorem

${c }^{2} = {a}^{2} + {b}^{2}$
${9 }^{2} = {7}^{2} + {b}^{2}$
$81 = 49+ {b}^{2}$
$81 - 49 = {b}^{2}$
$32= {b}^{2}$
Take square root of both sides

$b = \sqrt{32}$
$b = 4 \sqrt{2}$

5 0

4 years ago

Read 2 more answers

What is the boundary line for the linear inequality 4x + 2y < 18?

Cloud [144]

Answer:

Simplifying

x = 4.5 + -0.5y

Step-by-step explanation:

4 0

3 years ago

A recreation center charges nonmembers $3 to use the pool and $5 to use the basketball courts. A person pays $42 to use the recr

Andrei [34K]

Let x = times in the pool
Let y = times in the basketball courts

42=3x+5y
x+y=12
Therefore y = 12-x
Subsitute for y
42 = 3x + 5(12-x)
42 = 3x + 60 -5x
Subtract 60
-18 = -2x
9 = x

The person used the pool 9 times.

5 0

3 years ago

HELP!!! Does the graph represent a function and if so, why? No, some of the ordered pairs in this list have the same second elem

vlabodo [156]

Answer:

No, some of the ordered pair in this graph have the same first element.

Step-by-step explanation:

The relation of a function is that it expresses a dependence of one element on another. There is a one to one relation, which means that one point can not be used more then once.

Some ordered pairs in this graph have the same first element and are used more then once. So this graph can not represent a function.

3 0

3 years ago

Describe the surface in 3 represented by the equation x + y = 5. This is the set {(x, 5 − x, z)|x , z } which is a vertical plan

KengaRu [80]

treonvty trwqnty ewuit

7 0

3 years ago