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3 years ago

What is the maximum value that the graph of y=cos x assumes?

Mathematics

2 answers:

fredd [130]3 years ago

7 0

Answer:

Step-by-step explanation

Ksenya-84 [330]3 years ago

4 0

Answer: 1

Step-by-step explanation: the cosine function oscillates between the values -1 to 1

The amplitude of this particular function is understood to be 1

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WHAT ARE ALL PRIME NUMBERS X WHICH ARE <img src="https://tex.z-dn.net/?f=5%5C%20%5Ctextless%20%5C%20x%5Cleq%2019" id="TexFormula

ella [17]

Answer:

7, 11, 13, 17, 19

All of these numbers only have 1 and themselves as factors, and every other number can be written as a product of two or more primes, making the remaining number composite:

$6=2\cdot3\\8=2^3\\9=3^2\\10=2\cdot5\\12=2^2\cdot3\\14=2\cdot7\\15=3\cdot5\\16=2^4\\18=2\cdot3^2$

5 0

3 years ago

Read 2 more answers

This week laptops are 25% off.if a laptop cost $360 what it's sell price<br>

mihalych1998 [28]

Answer:

$270

Step-by-step explanation:

You can do this:

$360*0.75

8 0

4 years ago

Make six prime numbers using the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 once each.

lana [24]

Answer:

2, 3, 5, 7, 11, 13.

Step-by-step explanation:

A prime number is a number that you don't get a whole number when divided by 2 but you do get a whole number when divided by prime numbers such as 3,5,7,11... Basically a number with two factors, it can only be divided by 1 or themselves. for example:

9/2 = 4.5 (this is not a whole number so it might be a prime.

9/3 = 3 (it works when divided by a prime number.

another:

8/2 = 4 (it gives a whole number when divided by 2 therefor, it can't be a prime number.

Answering:

There are 6 prime numbers at the top^^^^.

8 0

3 years ago

Read 2 more answers

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ,0)left parenthesis, plus min

lora16 [44]

Answer:

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the relation between the focus and semi major axes and semi minor axes as:

$\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 } \\ \\ \mathbf{c^2 = 49 } \\ \\ \mathbf{c = \sqrt{49 }}$