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tester [92]
3 years ago
13

2 1/3 x 1 1/2 please help thank you

Mathematics
2 answers:
ehidna [41]3 years ago
6 0
Answer:
3.5

WORK:
 2 1/3 x 1 1/2 = 7/2 = 3 1/2 = 1.5



natta225 [31]3 years ago
5 0
3 1/3 x 1 1/2 = 5

(3 1/3 = 10/3)
( 1 1/2 = 3/2)
(10/3 x 3/2 = 30/6 = 5)
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A man enters a tall tower, needing to know its hieght. He notes that a long pendulum extends from the ceiling almost tothe floor and that its period is 15.5s. (a) How tall isthe tower? (b) If this pendulum is taken to the Moon,where the free-fall acceleration is 1.67m/s2, what isthe period there?T=15.5s(a) L=T2g/4π<span>2</span>
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3 years ago
Write the following quotient scientific notation 33x10 to the ninth power by 11x10 to the seventh power
zepelin [54]

Answer:

try 56

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10

Step-by-step explanation:

i feel that is the right awnser

6 0
2 years ago
Find the value of each missing variable. y=
e-lub [12.9K]

Step-by-step explanation:

29x - 3 + 15x + 7 = 180° because these two angles are supplementary

if we add like terms

44x + 4 = 180

44x = 176 divide both sides by 44

x = 4

29x - 3 = 13y - 17 because alternate exterior angles has same measurement

since we found the value of x let's rewrite the equation

4 × 29 - 3 = 13y - 17

113 = 13y - 17

130 = 13y divide both sides by 13

10 = y

7 0
3 years ago
Which expression is a factor of 12x2 + 29x – 8?
Contact [7]

Answer:

3x + 8, hope this helps.

4 0
3 years ago
Please help me with question number 2
Mice21 [21]

Answer:

2. The area of the side walk is approximately 217 m²

3. The distance away from the sprinkler the water can spread is approximately 11 feet

4. The area of the rug is 49.6

Step-by-step explanation:

2. The dimensions of the flower bed and the sidewalks are;

The diameter of the flower bed = 20 meters

The width of the circular side walk, x = 3 meters

Therefore, the diameter of the outer edge of the side walk, D, is given as follows

D = d + 2·x (The width of the side walk is applied to both side of the circular diameter)

∴ D  = 20 + 2×3 = 26

The area of the side walk = The area of the sidewalk and the side walk = The area of the flower bed

∴ The area of the side walk, A = π·D²/4 - π·d²/4

∴ A = 3.14 × 26²/4 - 3.14 × 20²/4 = 216.66

By rounding to the nearest whole number, the area of the side walk, A ≈ 217 m²

3. Given that the area formed by the circular pattern, A = 379.94 ft.², we have;

Area of a circle = π·r²

∴ Where 'r' represents how far it can spread, we have;

π·r² = 379.94

r = √(379.94 ft.²/π) ≈ 10.997211 ft.

Therefore, the distance away from the sprinkler the water can spread, r ≈ 11 feet

4. The circumference of the rug = 24.8 meters

The circumference of a circle, C = 2·π·r

Where;

r = The radius of the circle

π = 3.1

∴ For the rug of radius 'r', C = 2·π·r = 24.8

r = 24.8/(2·π) = 12.4/π = 12.4/3.1 = 4

The area = π·r²

∴ The area of the rug = 3.1 × 4² = 49.6.

8 0
2 years ago
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