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Strike441 [17]
3 years ago
13

In 20 minutes, i ate 1 1/2 sub sandwiches. <br /><br />

Mathematics
1 answer:
shtirl [24]3 years ago
7 0
A. sandwiches per hours is 4.5/hour
b. hours per sandwich is 0.33/sandwich
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Review the image below. Based on the image, what type of transformation is
podryga [215]

Answer:

When you read a sentence, you may first look for the subject or what the sentence is about. The subject usually appears at the beginning of a sentence as a noun or a pronoun. A noun is a word that identifies a person, place, thing, or idea. A pronoun is a word that replaces a noun. Common pronouns are I, he, she, it, you, they, and we. In the following sentences, the subject is underlined once.

Step-by-step explanation:

You will often read a sentence that has more than one noun or pronoun in it. You may encounter a group of words that includes a preposition with a noun or a pronoun. Prepositions connect a noun, pronoun, or verb to another word that describes or modifies that noun, pronoun, or verb. Common prepositions include in, on, under, near, by, with, and about. A group of words that begin with a preposition is called a prepositional phrase. A prepositional phrase begins with a preposition and modifies or describes a word. It cannot act as the subject of a sentence. The following circled phrases are examples of prepositional phrases.

4 0
3 years ago
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Use factoring to simplify the expression x^2-x-6/x-3 assume that x does not equal 3
Gre4nikov [31]
This works out beautifully.  You COULD use long division here, but since your numerator is a quadratic, your first instinct should be to try and factor it.  If you factor it, it works out to be (x - 3)(x + 2).  Now it just so happens that when you do that, the (x - 3) in the numerator will cancel with the (x - 3) in the denominator leaving you with one sad and lonely (x + 2) as your answer.
3 0
3 years ago
STILL GOING BAN ON THEM ANYWAY
iren [92.7K]

Answer:

I-

Step-by-step explanation:

Um okay.

7 0
3 years ago
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The function f(x)=125(0.9)x models the population of a species of fly in millions after x years.
SSSSS [86.1K]
A word to the wise:  It's  <span> f(x)=125(0.9)^x,   where ^ represents exponentiation.

In this case the ave. value over the interval [11, 15] is

 125(0.9)^15 - 125(0.9)^11
------------------------------------- = (125/4) [ 0.9^15 - 0.9^11)
               15 - 11                    =  (31.25) [ 0.2059 - 0.3138 ] = a negative result
                                              =  (31.25)(-0.1079) = -3.372  (av. r. of c.
                                                     over the interval [11,15] )

Do the same thing for the time interval [1,5].  Then compare the two rates of change.</span>
6 0
3 years ago
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andres has 4 bunches of balloons. there are 6 balloons in each bunchs how many balloons does andres have in all
Whitepunk [10]

\large{|\underline{\mathtt{\red{G}\blue{i}\orange{v}\pink{e}\blue{n}\purple{}\green{}\red{↯}\blue{}\orange{}}}}

1 bunch of balloons contain 6 balloons

\large{|\underline{\mathtt{\red{T}\blue{o}\orange{\:}\pink{F}\blue{i}\purple{n}\green{d}\red{↯}\blue{}\orange{}}}}

Number of balloons in 4 bunches = ?

\large\underline{\underline{\maltese{\purple{\pmb{\sf{\: Solution :-}}}}}}

  • <em>To</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>4</em><em> </em><em>bunches</em><em> </em><em>we</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>multiply</em><em> </em><em>the</em><em> </em><em>bumber</em><em> </em><em>of</em><em> </em><em>balloons</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>bunch</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>bunches</em><em>.</em>

\tt\multimap \: number \: of \: balloons \: in \: 1 \: bunch \times number \: of \: bunches

\sf \nrightarrow \: 6 \times 4 = 24

➪ <em>T</em><em>h</em><em>u</em><em>s</em><em>,</em><em> </em><em>T</em><em>h</em><em>e</em><em>r</em><em>e</em><em> </em><em>a</em><em>r</em><em>e</em><em> </em><em>2</em><em>4</em><em> </em><em>b</em><em>a</em><em>l</em><em>l</em><em>o</em><em>o</em><em>n</em><em>s</em><em> </em><em>i</em><em>n</em><em> </em><em>4</em><em> </em><em>b</em><em>u</em><em>n</em><em>c</em><em>h</em><em>e</em><em>s</em><em>.</em><em>.</em><em>.</em><em>~</em>

8 0
2 years ago
Read 2 more answers
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