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NikAS [45]
2 years ago
7

Janet rented a golf cart for $15, plus $16 per hour. She spent $111 to rent the golf cart. Which equation can be used to determi

ne the number of hours, h, Janet rented the golf cart?
A.
16h – 15 = 111

B.
16h + 15 = 111

C.
15h – 16 = 111

D.
15h + 16 = 111
Mathematics
2 answers:
artcher [175]2 years ago
5 0
B, h is represented as a constant (hourly) which would be next to 16, and adding up to a total of 111
vladimir1956 [14]2 years ago
3 0

Answer:

B.   16h + 15 = 111

Step-by-step explanation:

The equation should represent the initial cost plus the amount per hour (h) to equal $111 (the total amount spent).

Equation: 16h + 15 = 111

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Simplify<br>6^7/6^5<br>leaving your answer in index form.​
Juli2301 [7.4K]

Answer:

Step-by-step explanation: the and is 36.

8 0
3 years ago
suppose you have a dime, two pennies, and a quarter. one of the pennies was minted in 1976, and the other one was minted in 1992
notsponge [240]

The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

<h3>How to Solve Counting Problems?</h3>

A) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins. Let us label the dime as D, the penny as P, the quarter minted in 1976 as Q1 and the quarter minted in 1992 as Q2.

Now, if you choose one coin, you could choose either D, P, Q1, or Q2. This gives us 4 possible sets.

If you choose two coins, you choose the following sets of coins: DP, DQ1, DQ2, PQ1, PQ2, Q1Q2. This gives us 6 possible sets.

If you choose three coins, you could the following sets of coins: DPQ1, DPQ2, DQ1Q2, PQ1Q2. This gives us 4 possible sets.

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible set.

Therefore, the total number of different sets of coins you can form is 4 + 6 + 4 + 1 = 15 different sets of coins can be formed.

b) If you choose at least one coin, this means you could choose 1, 2, 3 or 4 coins.

If you choose one coin you could choose either D, P, Q1, or Q2. However, since Q1 and Q2 give us the same sum, they are effectively the same set. This gives us 3 possible sums (ten cents, one cent, or twenty-five cents.)

If you choose two coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DP, DQ, PQ, Q1Q2. This gives us 4 possible sums (11 cents, 35 cents, 26 cents, or fifty cents.)

If you choose three coins, you could choose the following sets of coins (since Q1 and Q2 are the same coin value, we can say Q for any instance where either one of these coins would be a possibility): DPQ, DQ1Q2, PQ1Q2. This gives us 3 possible sums (36 cents, 60 cents, or 51 cents).

If you choose four coins, you can only choose DPQ1Q2. This gives us 1 possible sum (61 cents.)

Therefore, the total number of different sums of coins you can form is 3 + 4 + 3 + 1 = 11 different sums of money can be produced.

c) The reason that the answers in part (a) and part (b) are not the same is because Q1 and Q2 are treated as two different coins in part (a) whereas they are effectively treated as the same coin in part (b). The reason they are treated as one coin is because they both contribute the same amount to the sum of money.

Read more about Counting Problems at; brainly.com/question/13875198

#SPJ1

3 0
2 years ago
Suppose u=&lt;2,−1&gt; and v=&lt;1,−8&gt; are two vectors that form the sides of a parallelogram. Then the lengths of the two di
tigry1 [53]
| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
 (2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
8 0
3 years ago
There is one fifth of a sandwich to share equally between 2 people. How much of the sandwich will each person get? Use the numbe
babunello [35]

Answer:

one tenth of a sandwich

Step-by-step explanation:

4 0
3 years ago
HELP ME PLEASE
Mashutka [201]

Answer:

9 + \frac{n}{3} - 6 = 7

Step-by-step explanation:

Given

9 + \frac{n}{3} - 6

Required

Evaluate when n = 12

Substitute 12 for n in 9 + \frac{n}{3} - 6

9 + \frac{n}{3} - 6 = 9 + \frac{12}{3} - 6

Simplify the fraction

9 + \frac{n}{3} - 6 = 9 + 4 - 6

9 + \frac{n}{3} - 6 = 7

4 0
3 years ago
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