Answer:
The second equation is correct.
y=2.25x + 4
Step-by-step explanation:
We can systematically eliminate the others.
For equation 3 and 4, 6.5*2 and 12*x is already bigger than 8 of the first set of numbers.
For equation 1, 2*x+8.5 is also bigger than 8 from the first set.
Plugging in the values to equation 2, we always get the correct cost.
There are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned from 14 volunteers.
Given that a school dance committee has 14 volunteers and each dance requires 3 volunteers at the door, 5 volunteers on the floor and 6 on floaters.
We are required to find the number of ways in which the volunteers can be assigned.
Combinations means finding the ways in which the things can be choosed to make a new thing or to do something else.
n
=n!/r!(n-r)!
Number of ways in which the volunteers can be assigned is equal to the following:
Since 2 have not been assigned so left over volunteers are 14-2=12 volunteers.
Number of ways =14
=14!/12!(14-12)!
=14!/12!*2!
=14*13/2*1
=91 ways
Hence there are 91 such ways in whih the volunteers can be assigned if two of them cannot be assigned.
Learn more about combinations at brainly.com/question/11732255
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Answer:
x = 18 or x = -12.
Step-by-step explanation:
||x-3|-5| = 10 only if |x-3|-5 = 10 or |x-3|-5 = -10, i.e., if |x-3|=15 or |x-3|=-5; but |x-3| cannot be equal to -5, because |x-3| should be a non-negative value. Therefore, the first equation is true only if |x-3|=15. |x-3| = 15 only if x-3 = 15 or x-3 = -15, i.e., x = 18 or x = -12. We can verify this in the following way: ||18-3|-5|=||15|-5|=|10|=10 and ||-12-3|-5|=||-15|-5|=|15-5|=|10|=10. This verify that our solution is correct.
Answer:
B. 1/4
Step-by-step explanation:
Even though A is a fraction it is also an integer (4)
2 boys 4 girls Add those together then divid And Then Use diffences And theres ur Awnser