The time spent, in hours, of teenagers on social media per year are normally distributed with a population standard deviation of
1 answer:
Answer:
1329.85≤μ≤1330.14
Step-by-step explanation:
z score for 99% confidence interval
from the z table we can find that the score for 99% confidence is 2.58
formula
z=}[/tex]}[/tex]
where
x-sample mean
μ-population mean
σ-population standard deviation
n-sample size
2.58=}[/tex]}[/tex]
1330-2.58×24÷442≤μ≤1330+2.58×24÷442
1329.85≤μ≤1330.14
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<h3>According to the given information:</h3>Let S be the number of hours it would take Sharon to paint the shed alone.
Kelly alone can paint the shed in T hours,
so she can paint (1/T) of a shed per hour.
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S = 5T/(T - 5)
According to the solving the correct expression of the given data is:
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