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3 years ago

A data analyst has spreadsheets numbered

Mathematics

1 answer:

algol [13]3 years ago

8 0

Answer:

$\frac{2}{9}$

Step-by-step explanation:

${\textrm}{Total number of objects here} = 9$

(2 spreadsheets, 3 databases and 4 presentations,

${\textrm}({Total} = 2+3+4 = 9)$

${\textrm}{No. of databases with an odd number} = 2 {\textrm}{(databases with number 1 and 3})$

As not mentioned other wise equal chances of all the outcomes is assumed so, by the classical definition of probability,

P(The chosen item is a odd numbered database)

= $\frac{2}{9}$

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An item is regularly priced at $90. It is on sale for 30% off the regular price. What is the sale price

madreJ [45]

Answer:

Step-by-step explanation:

Because 30 percent of 90 equals 27

Thus

90 - 27 = 63.

Please mark brainliest and give 5 stars.

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3 years ago

A sandwich costs 5:70 and a piece of fruit costs 2:15 if you have a 20 bill, how much change will you get ?

Gelneren [198K]

Well if you buy only 1 of each, it would cost you 7.85 in total. if you subtract that from 20, it equals 12.15.
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3 years ago

if a taxi charges $3.50 for the first on-fifth of a mile, then $0.55 cents for each additional one-fifth mile, how far can one t

34kurt

Let's forget for the tie being the cost ($3.5)of the 1st fifth of a mile:

Taxi charge excluding $3.5, is $13.95 - $3.5 = $10.45.

If each of the 5th (1/5) of a mile costs $0.55, then with $10.45 we can drive:
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3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

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3 years ago

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erastova [34]

Answer:

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Step-by-step explanation:

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2 years ago