Answer:
Explanation:
Hello,
In this case, since one drop equals 0.05 mL of the given solution, for a concentration 0.02 g/mL, the grams of oleic acid in one drop turns turn out:
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Answer:
11.76
Explanation:
Potassium hydroxide is a strong base that dissociates completely according to the following reaction.
KOH(aq) → K⁺ + OH⁻
Then, the concentration of OH⁻ will be 0.00580 M.
The pOH of the solution is:
pOH = -log [OH⁻]
pOH = -log 0.00580 = 2.24
We can calculate the pH using the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 - 2.24 = 11.76
Copie no caderno e complete as ligações simples, duplas e triplas que estão faltando nas seguintes estruturas<span>.</span>
POH will be -log[conc of OH]
-log (3.9E-08) = 7.409
pH = 14- pOH
pH = 14 - 7.409
pH = 6.59