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Zanzabum
4 years ago
12

How are elements similar to those in the same group on the periodic table ​

Chemistry
1 answer:
enot [183]4 years ago
5 0

Answer:

All the members of a group of elements have the same number of valence electrons and similar chemical properties.

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.

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In the quantum mechanical model, what two words do they use to describe<br> particles?
miskamm [114]

Answer:

This question is incomplete

Explanation:

This question is incomplete but one can assume the answer from the definition of quantum mechanics. Quantum mechanics is the science that describes particles in nature at the atomic and subatomic particle (electron, proton and neutron) level. Thus it can be assumed that atoms and subatomic particles are used to broadly describe particles.

5 0
3 years ago
How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?
taurus [48]
Moles=concentration x volume. 1.5/1000 multiply 0.450 = 6.75x10^-4
To find the mass of fecl3, we have the formula, mass=moles x molar mass. 6.75x10^-4 x (55.8+35.5 x 3). = 0.1096g

Not sure tho if i did it right
6 0
3 years ago
What is <br> 78.432 miles x 322.3 miles
Phoenix [80]
That would be 25,270.7904 miles
8 0
3 years ago
32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa)?
kotegsom [21]
Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

From the periodic table:
molar mass of oxygen = 16 gm
molar mass of hydrogen = 1 gm
Thus, the molar mass of water vapor = 2(1) + 16 = 18 gm

18 gm of water occupies 22.4 liters, therefore:
volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters

5 0
3 years ago
g modenr vacuum pumps make it easy to attain pressures of the order of in the laboratory. at a preasusure of 6.75 atm and an ord
Ratling [72]

Answer:

Number of molecules = 1.8267×10^20

Explanation:

From the question, we can deuced that the gases behave ideally, the we can make use of the ideal gas equation, which is expressed below;

PV = nRT

where

P =pressure

V =volume

n = the number of moles

R is the gas constant equal to 0.0821 L·atm/mol·K

T is the absolute temperature

Given:

P = 6.75 atm;

T = 290.0 k,

; V = 1.07 cm³ = 0.001 L

( 6.75 atm)(0.00107 L) = n(0.0821 L·atm/mol·K)(290K)

n = 3.0335167*10^-4 moles

But there are 6.022×10²³ molecules in 1 mole,

Number of molecules = 1.8267×10^20

7 0
3 years ago
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