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trasher [3.6K]
3 years ago
10

Which of the following definitions best describes a parallel of latitude?

Chemistry
2 answers:
Alexxandr [17]3 years ago
8 0
I think the answer is A: a line that is drawn horizontally around the earth and is parallel to the Prime Meridian

Hope this helps:)
Yanka [14]3 years ago
3 0
A. I’m sorry if I’m wrong but I’m 70% sure! Or C... most likely a!!
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if a sample of gas at 25.2 c has a volume of 536mL at 637 torr, what will its volume be if the pressure is increased to 712 torr
nignag [31]
Considering ideal gas:
PV= RTn

T= 25.2°C = 298.2 K

P1= 637 torr = 0.8382 atm

V1= 536 mL = 0.536 L

:. R=0.082 atm.L/K.mol

:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))

:. n= O.0184 mol

Then,
P2= 712 torr = 0.936842 atm

V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)

:.V2 = 0.4796 L
OR
V2 = 479.6 ml

6 0
3 years ago
For an ideal gas, evaluate the volume occupied by 0.3 mole of gas.
Serhud [2]

Answer:

V=0.3×22.4=6.72 liters hope this helps

8 0
2 years ago
In what can wax harmful
Tanzania [10]
GEORGEOCTOBER 18, 2012Floor Wax is Harmful to the Environment

Floor wax is applied on floor surfaces to make it scuff-resistant, water-resistant, slip resistant and glossy. It provides a thin, protective and hard surface layer when applied to flooring. Conventional floor wax has five main ingredients and each one of them has detrimental effects on the environment, not to mention the chemical waste created by the continuous upkeep required. The cumulative effects of these ingredients on the environmental render their harmful actions more potent and difficult to reverse.

6 0
3 years ago
Which trait enables a polar bear to survive an extremely cold climate.
blondinia [14]
Thick fur helps a polar bear survive
8 0
3 years ago
Read 2 more answers
At a certain temperature the rate of this reaction is second order in NH4OH with a rate constant of 34.1 M^-1s^-1: Suppose a ves
Tom [10]

Answer:

Time = 0.929s = 0.93s (2 s.f)

Explanation:

Rate constant, k = 34.1 M^-1s^-1

Initial Concentration, [A]o = 0.100M

Time = ?

Final Concentration [A] = 0.0240M

The parameters are represented in the following equation as;

1/[A] = kt + 1/[A]o

kt = 1/[A]  -  1/[A]o

kt = 1/0.0240 - 1/0.1

kt = 31.67

t = 31.67 / 34.1

t = 0.929s = 0.93s (2 s.f)

5 0
3 years ago
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