All categories

3 years ago

1 Write an equation where a number is added to a variable, and a solution is -8.

Mathematics

1 answer:

aniked [119]3 years ago

7 0

Answer:

n+v= -8

Step-by-step explanation:

number=n; variable=v

n+v=-8

You might be interested in

CAN SOMEONE PLZZ HELP ME THE LAST QUESTION PLZZZZZ?????

MissTica

first is proportional. y is 1 and 1/4 times x

second is not proportional.

reason? divided any y value by its corresponding x value and you'll keep getting 1.25, or 1 and 1/4. and the second one is not proportional because dividing the y values by their corresponding x value will give different answers.

maybe im wrong maybe im right you choose to trust me or not.

5 0

3 years ago

Use mulipation to find 2 equivalent fractions

laila [671]

1/2 is equivalent to 2/4 because,

2(1/2) = 2/4

So as you can see if you multiply the numerator(top) and the denominator(bottom) by the same number, you get an equivalent fraction! In my example you can see that I multiplied both by 2.

5 0

3 years ago

Mark spent 1/3 of an hour reading his Bible. How many minutes did he read his Bible?

madam [21]

Answer:

20 minutes

Step-by-step explanation:

60/3=20

hope this helps :)

5 0

3 years ago

Helppppopleaseee????

rosijanka [135]

Answer:

LQ = 5

Median = 6

Step-by-step explanation:

$\frac{n+1}{2}$ gives us 5.5, so we do the average of position 5 and 6. This gives us 6, so the median is 6.

Now we find the median of the bottom half of the numbers, which is 5, so the LQ is 5.

Now we find the median of the upper half of the numbers, which is 7, so the UQ is 7.

7 0

2 years ago

What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3

andrew-mc [135]

Solve 4x − 3y = 3 and 5x − 4y = 3

Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
 $\frac{4x}{4} = \frac{3x+3}{4}$ [Divide both sides by 4]
x= $\frac{3}{4}y+ \frac{3}{4}$

Step 2: Substitute $\frac{3}{4}y+ \frac{3}{4}$ for x in 5x-4y=3
5x-4y=3
5( $\frac{3}{4}y+ \frac{3}{4}$ )-4y=3
 $\frac{-1}{4}y+ \frac{15}{4} =3$
$\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4}$ [Subtract $\frac{15}{4}$ to both sides]
$\frac{-1}{4}y= \frac{-3}{4}$
$\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }= \frac{\frac{-3}{4} }{ \frac{-1}{4}}$ [Divide both sides by $\frac{-1}{4}$ ]
y = 3

Step 3: Substitute 3 for y in x = $\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}y+ \frac{3}{4}$
$\frac{3}{4}(3)+ \frac{3}{4}$
x = 3

5 0

3 years ago