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GaryK [48]
3 years ago
12

If Pay(hours) is the function that describes Al's monthly pay at BIT Labs based on his training, Pay(22 hours), Pay(22), and P(2

2) all represent what?
A. Work required to get 22 hours of training
B. Hours of training for $22/hour pay
C. Monthly pay with 22 hours of training
D. Pay earned for 22 hours worth of work
Mathematics
1 answer:
maw [93]3 years ago
3 0
<span>If Pay(hours) is the function that describes Al's monthly pay at BIT Labs based on his training, Pay(22 hours), Pay(22), and P(22) all represent what? c
</span>
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Find p if 4P = 0.25<br>​
Andrej [43]

Answer:

p= 0.0625

Step-by-step explanation:

p=0.25/4

plz mark brainliest

8 0
2 years ago
Read 2 more answers
What's the answer please
worty [1.4K]
12^2 - 11^2
= 144 - 121 
= 23

square root (23) = 4.79 = 4.8

answer
C. 4.8
7 0
3 years ago
For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
What is the value of x log3x equals 4
ArbitrLikvidat [17]

~~~~\log_3 (x) = 4\\\\\implies x= 3^4 \\\\\implies x= 81

7 0
1 year ago
Find the value of x. I need help thank you! :)​
kondor19780726 [428]

Answer:

47

Step-by-step explanation:

Hope this helps. Let me know if you have any questions.

8 0
3 years ago
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