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Phantasy [73]
3 years ago
12

Suppose that in a bushel of 100 apples there are 20 that have worms in them and 15 that have bruises. Only those apples with nei

ther worms nor bruises can be sold. If there are 10 bruised apples that have worms in them, how many of the 100 apples can be sold?
Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

65 apples could be sold

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Please help me asapp
Ede4ka [16]

Answer:

<h2>It is h=1.5 yd</h2>

Step-by-step explanation:

a = b \times h \\ \\  a = 9 \:  \:  {yd}^{2}  \\ b = 6 \:  \: yd \\  \\ 9 = 6 \times h \\ h =  \frac{9}{6}  \\ h = 1.5 \:  \: yd

I hope that is useful for you :)

6 0
3 years ago
Examine the statement.
azamat

Answer/Explanation:

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5 0
3 years ago
Find the simplified product:
Ratling [72]

Answer:

3 {x}^{4}

Step-by-step explanation:

\huge \sqrt[3]{9 {x}^{4} } .  \sqrt[3]{3 {x}^{8} }  \\  \\ \huge =  \sqrt[3]{9 {x}^{4} \times 3 {x}^{8}  }  \\  \\\huge  =  \sqrt[3]{27 {x}^{12}  }  \\  \\  \huge\orange{= 3 {x}^{4} }

8 0
2 years ago
The first term of a sequence is 9 and the common difference is 5. Which of the following is the fifth term of the sequence?
spayn [35]

Answer:

29

Step-by-step explanation:

9+5=14+5=19+5=24+5=29

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3 years ago
Evaluate the expression for x = 2 and y = 4.
Lelu [443]

Answer:

Not enough info

Step-by-step explanation:

Not enough info sry

7 0
2 years ago
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