Use the trig identity
2*sin(A)*cos(A) = sin(2*A)
to get
sin(A)*cos(A) = (1/2)*sin(2*A)
So to find the max of sin(A)*cos(A), we can find the max of (1/2)*sin(2*A)
It turns out that sin(x) maxes out at 1 where x can be any expression you want. In this case, x = 2*A.
So (1/2)*sin(2*A) maxes out at (1/2)*1 = 1/2 = 0.5
The greatest value of sin(A)*cos(A) is 1/2 = 0.5
Answer:
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Answer:
Table 3
Step-by-step explanation:
Check table three;
Since the left hand limit 
is not equal to the right hand limit 
, the limit as x approaches to 2 does not exist.
Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2
Answer:
117 cups
Step-by-step explanation:
two dozen cookies calls for 234cups of sugar
2 dozen cookies = 234 cups of sugar
How much sugar is needed to make one dozen cookies?
Let x = cups of sugar needed
1 dozen cookies = x cups of sugar
2 dozen cookies : 234 cups of sugar = 1 dozen cookies : x cups of sugar
2 : 234 = 1 : x
2 / 234 = 1 / x
Cross product
2*x = 234 * 1
2x = 234
x = 234 / 2
= 117 cups
Your options are wrong because none corresponds with the answer
