2/7 ( k+5/8) = 2 and 2/7
2/7 (k+5/8) = 16/7 |multiply by 7
2(k+5/8) = 16 |divide by 2
k+5/8 = 8 |subtract 5/8
k=8-5/8 = 7 and 3/8 = 27/8 = 7.375
= 9a(5x² + 3x + 2)
The distributive property lets you remove the same factor from all terms and write it outside parentheses.
Answer:
- large: 18.5 kg
- small: 15.75 kg
Step-by-step explanation:
Let b and s represent the weights of the big and small boxes, respectively. Then the two delivered weights can be summarized as ...
5b +6s = 187
3b +2s = 87
We can eliminate the "s" variable by subtracting the first equation from 3 times the second:
3(3b +2s) -(5b +6s) = 3(87) -(187)
4b = 74 . . . . . collect terms
b = 18.5 . . . . . divide by 4
Using this value in the second equation, we find ...
3(18.5) +2s = 87
2s = 31.5 . . . . . . . . subtract 55.5
s = 15.75 . . . . . . . . divide by 2
The large box weighs 18.5 kg; the small box weighs 15.75 kg.
Answer:
3.5
Step-by-step explanation:
98/8=12.25
√12.25=3.5
Answer:
see explanation
Step-by-step explanation:
(a)
The angle around the centre O of the circle = 360°, then
∠ AOB = 360° - 260° = 100°
Δ AOB is isosceles ( the radii OA and OB are congruent )
The altitude from O bisects ∠ AOB , thus
y = 50°
Since the triangle is isosceles the 2 base angles are congruent, so
x = 
= 
= 40°
(b)
∠ POR = 360° - 254° = 106°
Δ POR is isosceles (the radii OP and OR are congruent ) , then
the 2 base angles are congruent , thus
a = 
= 
= 37°
