Answer:
2 to the power of one sixth
Step-by-step explanation:
Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:
![\sqrt[n]{x} = {x}^{ \frac{1}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%3D%20%20%7Bx%7D%5E%7B%20%5Cfrac%7B1%7D%7Bn%7D%20%7D%20)
So you can rewrite the given fraction as

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

Since

the answer is
![{2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}](https://tex.z-dn.net/?f=%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B6%7D%20%7D%20%20%5C%3A%20or%20%5C%3A%20%20%5Csqrt%5B6%5D%7B2%7D%20)
Answer:
B
Step-by-step explanation:
The answer to the problem is 5
Answer:
18. 46
19. 0.7
22. 4 3/4
23. 54.5
26. 14
27. 11.5
31. 15
etc.
Step-by-step explanation:
absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:
absolute value of 46 = 46
absolute value of - 36 = 36
(imagine the sign in front of the # isn't there)