Question

27. 2392 Two identical charged particles are 3.8 cm apart from each other and particle 1 exerts a force of 5x10-9 N on particle 2. Part Description Answer Save Status A. What is the charge on each particle? (include units with answer) 4.011*10^-22 C Format Check OK - using first value as 4.010e-13 nC Click here to check your answer 3.5 pts.88% 13% try penalty 8 try limit # tries: 1

Answer 1

Answer:

The charge on each particle is  $q =2.832 *10^{-11} C$

Explanation:

From he question we are told that

      The distance of separation between particles is  $d = 3.8 cm = 0.038m$

       The force exerted by on of the charged particle on the other charge particles is $F = 5 *10^{-9}$

 

Generally the between these charge particle can be mathematically represented as

        $F = \frac{k q_1 q_2 }{d^2}$

  Where k is the colombe constant with a value of  $k = 9*10^9\ kg \dot m^3 \cdot s^{-4} A^{-2}$

Since the charge are identical

         $q_1 = q_2 = q$  

So the equation becomes

          $F = \frac{k q^2 }{d^2}$

Making q the subject of the formula

          $q =\sqrt{ \frac{F * d^2 }{k}}$

Substituting values

         $q =\sqrt{ \frac{5*10^{- 9} * 0.038^2 }{9*10^9}}$

        $q =2.832 *10^{-11} C$