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nadezda [96]
3 years ago
14

Cylinder A is moving downward with a velocity of 3 m/s when the brake is suddenly applied to the drum. Knowing that the cylinder

moves 6 m downward before coming to rest and assuming uniformly accelerated motion, determine (a) the angular acceleration of the drum, (b) the time required for the cylinder to come to rest.
Physics
1 answer:
Xelga [282]3 years ago
7 0

Answer:

Incomplete question

Check attachment for the given diagram

Explanation:

Given that,

Initial Velocity of drum

u=3m/s

Distance travelled before coming to rest is 6m

Since it comes to rest, then, the final velocity is 0m/s

v=3m/s

Using equation of motion to calculate the linear acceleration or tangential acceleration

v²=u²+2as

0²=3²+2×a×6

0=9+12a

12a=-9

Then, a=-9/12

a=-0.75m/s²

The negative sign shows that the cylinder is decelerating.

Then, a=0.75m/s²

So, using the relationship between linear acceleration and angular acceleration.

a=αr

Where

a is linear acceleration

α is angular acceleration

And r is radius

α=a/r

From the diagram r=250mm=0.25m

Then,

α=0.75/0.25

α =3rad/sec²

The angular acceleration is =3rad/s²

b. Time take to come to rest

Using equation of motion

v=u+at

0=3-0.75t

0.75t=3

Then, t=3/0.75

t=4 secs

The time take to come to rest is 4s

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4 0
3 years ago
Two identical silver spheres of mass m and radius r are placed a distance R (sphere 1) and 2R (sphere 2) from the Sun, respectiv
lys-0071 [83]

Answer:

The ratio of T2 to T1 is 1.0

Explanation:

The gravitational force exerted on each sphere by the sun is inversely proporational to the square of the distance between the sun and each of the spheres.

Provided that the two spheres have the same radius r, the pressure of solar radiation too, is inversely proportional to the square of the distance of each sphere from the sun.

Let F₁ and F₂ = gravitational force of the sun on the first and second sphere respectively

P₁ and P₂ = Pressure of solar radiation on the first and second sphere respectively

M = mass of the Sun

m = mass of the spheres, equal masses.

For the first sphere that is distance R from the sun.

F₁ = (GmM/R²)

P₁ = (k/R²)

T₁ = (F₁/P₁) = (GmM/k)

For the second sphere that is at a distance 2R from the sun

F₂ = [GmM/(2R)²] = (GmM/4R²)

P₂ = [k/(2R)²] = (k/4R²)

T₂ = (F₂/P₂) = (GmM/k)

(T₁/T₂) = (GmM/k) ÷ (GmM/k) = 1.0

Hope this Helps!!!

3 0
3 years ago
Rearrange the formula for mechanical energy to solve for height:
docker41 [41]

Explanation:

Given formula:

            ME=\frac{1}{2}mv²+mgh

  To make height the subject of the formula, follow the following procedures;

     Subtract \frac{1}{2}mv² from both side of equation

 M.E - \frac{1}{2}mv² = \frac{1}{2}mv² - \frac{1}{2}mv²+mgh

                  This gives:

                        M.E - \frac{1}{2}mv² = mgh

Multiply both sides of the expression by \frac{1}{mg}

  ( M.E -  \frac{1}{2}mv² ) x  \frac{1}{mg} =  \frac{1}{mg} x mgh

       h = ( M.E -  \frac{1}{2}mv² ) x  \frac{1}{mg}

Learn more:

Kinetic energy brainly.com/question/6536722

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4 0
3 years ago
The coefficients of static and kinetic frictions for plastic on wood are 0.50 and 0.40,respectively. How much horizontal force w
IrinaK [193]

The horizontal force needed to start the calculator moving from rest is 1.5 N

What is Kinetic friction?

It is defined as a force that acts between moving surfaces.

The magnitude of the force will depend on the coefficient of kinetic friction between the two materials.

Here,

weight of calculator, N = 3 N

The coefficients of static frictions, µ (static) = 0.50

The coefficients of kinetic frictions, µ (kinetic) = 0.40

Now,

The horizontal force required = The static friction force

F = µ (static) * weight of calculator

F = 0.50 * 3.0

F = 1.5 N

Hence,

The horizontal force needed to start the calculator moving from rest is 1.5 N

Learn more about   horizontal force here:

<u>brainly.com/question/21481680</u>

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How could you record the number 4000 and report 2 significant figures?
yawa3891 [41]

Explanation:

Write in scientific notation.

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