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Misha Larkins [42]
3 years ago
15

If the sides of a triangle are 3,4, and 5, then, to the nearest degree , the measure of the smallest angle of the triangle is?

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

37 Degrees

Step-by-step explanation:

arc tan(3/4) = 36.869 degrees

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Step-by-step explanation:

\cos \theta  =  \frac{1}{ \sec\theta }  =  -  \frac{3}{ \sqrt{30} }  =  -  \frac{3 \sqrt{30} }{30}   =  -  \frac{ \sqrt{30} }{10}

\cos( \frac{\pi}{2} -  \theta )=  \cos \frac{\pi}{2}  \cos \theta  +   \sin \frac{\pi}{2}  \sin \theta

Note that

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Given that ∠B ≅ ∠C.

to prove that the sides AB = AC

This can be done by the method of contradiction.  

If possible let AB \neq=AC

Then either AB>AC or AB<AC

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