Current amount in account
P=36948.61
Future value of this amount after n years at i=11% annual interest
F1=P(1+i)^n
=36948.61(1.11)^n
Future value of $3000 annual deposits after n years at i=11%
F2=A((1+i)^n-1)/i
=3000(1.11^n-1)/0.11
We'd like to have F1+F2=280000, so forming following equation:
F1+F2=280000
=>
36948.61(1.11)^n+3000(1.11^n-1)/0.11=280000
We can solve this by trial and error.
The rule of 72 tells us that money at 11% deposited will double in 72/11=6.5 years, approximately.
The initial amount of 36948.61 will become 4 times as much in 13 years, equal to approximately 147800 by then.
Meanwhile the 3000 a year for 13 years has a total of 39000. It will only grow about half as fast, namely doubling in about 13 years, or worth 78000.
Future value at 13 years = 147800+78000=225800.
That will take approximately 2 more years, or 225800*1.11^2=278000.
So our first guess is 15 years, and calculate the target amount
=36948.61(1.11)^15+3000(1.11^15-1)/0.11
=280000.01, right on.
So it takes 15.00 years to reach the goal of 280000 years.
Answer:
The Question isn't clear
Step-by-step explanation:
Wow matrixes gg
a)[ 1 1 4 ]
[-7 -6 -1 ]
[ 0 4 0 ]
b)[ 15 12 12 ]
[-12 -12 0 ]
[3 6 0 ]
c)[ 7 4 12 ]
[ -18 -16 -2 ]
[ 1 10 0 ]
d) I forgot how to do d lol so heres all I got.
Answer:
All you have to do is subtract!
<em>1753 - 887</em> = 866
Therefore, Marco scored 866 more points than Jasmine. Hope this helped! :)
Answer:
sorry but I really don't know the answer.
Step-by-step explanation:
