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Zepler [3.9K]
2 years ago
13

What is the quotient of 1,456 and 7?

Mathematics
2 answers:
denis-greek [22]2 years ago
7 0

Answer: My fellow friend, it’s 208!

Step-by-step explanation:

Anestetic [448]2 years ago
4 0

<em>da answer is </em>

<u>208 </u>

hope that heps teddy~

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A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that repr
Mashcka [7]

Answer:

A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a

Step-by-step explanation:

6 0
3 years ago
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Find the 8th term in the geometric sequence below. 65,536, 24,576, 9,216, 3,456, 1,296, …
Ad libitum [116K]
The answer to this question is -121584
4 0
3 years ago
3. Multiply (-7)(2)(-2). (5 points)<br> 1. -28<br> 2. -14<br> 3. 28<br> 4. 14
Rashid [163]

Answer:

28

Step-by-step explanation:

-7x2 is -14

-14x-2 is positive 28.

5 0
3 years ago
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FILL IN THE BLANKS: Given P(x) = 3x5 + 7x6 + 11x7 – 12x - 10
Mama L [17]

The polynomial  3x^5 + 7x^6 + 11x^7 - 12x - 10 is in standard form if the exponents are arranged in decreasing order.

<h3>Polynomial in Standard Form</h3>

Polynomial is an algebraic expression with one or more terms. For example :2x^3+6x^4+x^2+x+2. In this example and in your exercise the exponents of the terms are not arranged in order.

Um polynomial is in <u>Standard Form</u> when the exponents of the terms are in decreasing order. See more details below.

2x^3+6x^4+x^2+x+2is not in standard form because the exponents are not written in decreasing order.

6x^4+2x^3++x^2+x+2 is in standard form because the exponents are written in decreasing order.

Therefore, the given polynomial will be in standard form if yours exponents are arranged in decreasing order.

Read more about polynomials here:

brainly.com/question/4142886

4 0
2 years ago
The 21st, 37th and 56th term of an A.P. are consecutive terms of a G.P. Find the common ratio of the G.P.​
mash [69]

just use what you know about this stuff

(a+36d)/(a+20d) = (a+55d)/(a+36d)

(a+36d)^2 = (a+55d)(a+20d)

a^2+72ad+1296d^2 = a^2+75ad+1100d^2

3ad = 196d^2

3a = 196d

That is, for any value of n,

a=196n

d=3n

So, there is no unique solution.

If n=1, then a=196 and d=3. The terms are

196+20*3 = 256

196+36*3 = 304

196+55*3 = 361

304/256 = 361/304

You can easily verify that it works for any value of n.

6 0
3 years ago
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