In 1 mole of , there are 3 moles of ions, 1 mole of Ca^{2+} and 2 mole of
.
Molar mass of is 110.98 g/mol. Calculating number of moles from given mass as follows:
Thus, number of moles of ions will be .
Since, 1 mole of any substance has units of that substance where
is Avogadro's number.
Thus, 9.38 mol of ions will have number of ions.
Therefore, total number of ions in 347 g of is
.
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For :
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of :
Moles of = 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of
1 mole of NaOH react with 1/2 mole of
0.1241 moles of NaOH react with (1/2)×0.1241 mole of
Moles of that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of :
<u>Concentration of = 0.7246 M</u>