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lorasvet [3.4K]
3 years ago
13

What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4

.18 J/g°C.
Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer : The amount of heat required is, 1672 J

Solution :

Formula used :

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

where,

Q = heat required = ?

m = mass of water = 20 g

c = specific heat of water = 4.18J/g^oC      

\Delta T=\text{Change in temperature}  

T_{final} = final temperature = 30^oC

T_{initial} = initial temperature = 10^oC

Now put all the given values in the above formula, we get the amount of heat required.

Q=20g\times 4.18J/g^oC\times (30-10)^oC

Q=1672J

Therefore, the amount of heat required is, 1672 J

EastWind [94]3 years ago
5 0
Q=MCdeltaT
*make sure you change celcius into Kelvin*
Q=20(4.18)(20)
Q=1,672

It requires 1,672 Joules
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