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3 years ago

Standard form four hundred and five hundredths

Mathematics

2 answers:

galben [10]3 years ago

8 0

400.05 is the answer.

Ainat [17]3 years ago

7 0

400.5 is your wander

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How to to this problem

bulgar [2K]

Can you post a clearer picture?

7 0

3 years ago

In f(x) = 2x2 − 8x − 10, the y-intercept is ? at ? and the x-intercepts are (-1, 0) and ? .

IgorLugansk [536]

<h2>1. y-intercept</h2>

$\boxed{(0,-10)}$

The quadratic function $f(x)=2x^22-8x-10$ represents a parabola. In fact, the graph of a quadratic function is a special type of U-shaped curve called a parabola. To find the y intercept, we set $x=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ x=0 \rightarrow f(0)=-10 \\ \\ Then \ y-intercept: \\ \\ (0,-10)$

<h2>2. x-intercepts</h2>

$\boxed{(-1,0) \ and \ (5,0)}$

To find the other x-intercept, we must set $y=0$ as follows:

$f(x)=2x^2-8x-10 \\ \\ If \ y=0 \rightarrow 2x^2-8x-10=0 \\ \\ Using \ the \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \therefore x=\frac{-(-8) \pm \sqrt{(-b)^2-4(2)(-10)}}{2(2)} \\ \\ \therefore x_{1}=-1 \ and \ x_{2}=5$

Therefore, the other x-intercept is $(5,0)$ . You can see both the y-intercept and the x-intercepts in the figure below.

8 0

3 years ago

If a 2 centimeter cube is placed inside a box that is 9 cm by 5 cm by 8cm ,

Bumek [7]

Answer:

360 cm3

Step-by-step explanation:

Option d is the right answer

8 0

3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

The equation models the (h) height in centimeters after (t) seconds of a weight ttached to the end of a spring that has been str

Elena L [17]

Answer:

t = 3 arc cos(h/7)/π

Step-by-step explanation:

The equation h=7cos(pi/3 t) models the (h) height in centimeters after (t) seconds of a weight attached to the end of a spring that has been stretched and released. To solve the equation for t we will solve the equation step by step:

h=7cos(pi/3 t)

Step 1)

Divide both sides by 7

h/7 = 7cos(pi/3 t)/7

Now the equation becomes h/7=cos(pi/3 t)

Step 2)

h/7=cos(pi/3 t)

Now apply inverse cosine function:

arc cos (h/7) = pi/3 t

Step 3)

t = 3 arc cos(h/7)/pi

Thus t = 3 arc cos(h/7)/pi ....

6 0

3 years ago