Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :![A=P(1+r)^t](https://tex.z-dn.net/?f=A%3DP%281%2Br%29%5Et)
![A=5000(1+0.04)^3](https://tex.z-dn.net/?f=A%3D5000%281%2B0.04%29%5E3)
A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : ![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{2})^{2 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B2%7D%29%5E%7B2%20%5Ctimes%203%7D)
A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : ![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{4})^{4 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B4%7D%29%5E%7B4%20%5Ctimes%203%7D)
A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{12})^{12 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B12%7D%29%5E%7B12%20%5Ctimes%203%7D)
A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Solving this requires use of conversions
we already know that
2.05 m > 2 m
all that's left is the question
200 cm vs. 2.05 meters
I we know our equivalencies, we know that
100 cm = 1 m
if this is so then
200 cm = 2 m
we already know that
2.05 m > 2 m
so it must also be that
2.05 m > 200 cm
100 centimeter in a meter
100*1=100
Answer:
B. false
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
(y-5) / (7-5) = (x-1) / (2-1)
(y-5) / 2 = x-1
y-5 = 2x -2
y = 2x +3