Answer:
f[g(1)] = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 1
g(x) = 3x - 2
<u>Step 2: Find g(1)</u>
- Substitute in <em>x</em>: g(1) = 3(1) - 2
- Multiply: g(1) = 3 - 2
- Subtract: g(1) = 1
<u>Step 3: Find f[g(1)]</u>
- Substitute in g(1): f[g(1)] = 2(1) + 1
- Multiply: f[g(1)] = 2 + 1
- Add: f[g(1)] = 3
The formula to find the midpoint of a segment is ((x1 + x2)/2,),(y1 + y2)/2).
The x coordinate of the first point is -4, and the x coordinate of the second point is -8. The y coordinate of the first point is 6, and the y coordinate of the second point is -2. Now, we can plug these into our formula.
((-4 + (-8))/2), (6 + (-2))/2)) = (-12/2), (4/2) = (-6, 2)
So, (-6, 2) is the midpoint of the segment.
Answer:
multiple by -3
and that will be the answer
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Answer:
- (x +1)² = 4
- (D) x = -1 ±2
Step-by-step explanation:
Start by getting the x-terms on one side of the equal sign. We can do that by subtracting x from both sides.
3 = x² +2x
Now, add the square of half the x-coefficient.
3 +1 = x² +2x +1
(x +1)² = 4 . . . . . . . . write as a square in the desired form
__
To solve, take the square root, and add the opposite of the left-side constant.
x +1 = ±2
x = -1 ±2 . . . . . . matches choice (D)
