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Lena [83]
3 years ago
11

Hannah loved mini-Snickers bars. She enjoyed making treats with them. She used 1/2 of her supply to make a blizzard. She froze 1

/4 of the remainder to enjoy later,and she used the rest to bake cookies. If she had 4 dozen to begin with, how many did she freeze? (PLEASE SHOW STEPS!)
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
4 dozen. That means she used half, she has 2 dozen left.  1/4 of that is 1/2 of a dozen, so she has 6 or 1/2 a dozen snickers bars left. Is this middle school? I am in middle school and my lessons are constant of proportionality!!
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There is a photo attached<br><br>tan 270 is incorrect!
wlad13 [49]

\dfrac{1-\cos135^\circ}{\sin135^\circ}=\dfrac{1-\left(\cos^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{1-\left(1-\sin^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\medskip\\=\dfrac{2\sin^2 67.5^\circ}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{\sin 67.5^\circ}{\cos 67.5^\circ}=\tan 67.5^\circ

3 0
3 years ago
What is 37% of 293? Plz help me people this is for tomorrow
stira [4]
108.41 i pretty sure
5 0
3 years ago
Read 2 more answers
Please help I need this for a text ASAP.
Sladkaya [172]

The values of x and y are 45 and 8.

<h3>What is a Linear Pair of Angles?</h3>

When two lines meet at a single point, a pair of linear angles is created. If the angles follow the point where the two lines cross, they are considered to be linear. A linear pair's angles add up to 180° in every case.

Given:

Measures of two linear pairs of angles which are of equal measures are 2x and 11y + 2.

As the sum of linear pair of angles is 180°, and if they are of equal measures, each angle must be equal to 90°.

To determine the values of x and y we equate the given angles to 90°.

2x = 90°

⇒ x = 45

And 11y+2 = 90°

⇒ 11y = 90-2 = 88

⇒ y = 8

To know more about linear pairs visit:

brainly.com/question/17525542

#SPJ13

8 0
1 year ago
Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)
Contact [7]

cosU:-

\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25

As U lies in Q3

  • cosU=-24/25

sinV

\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4

As V lies in Q3

  • sinV=-3/5

So

  • sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=<u>4</u><u>4</u><u>/</u><u>1</u><u>2</u><u>5</u>
  • cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125
3 0
2 years ago
The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 292 people entered the park, a
motikmotik

Answer:

<u>112 children</u>

<u>180 adults</u>

Step-by-step explanation:

Let the number of adults = A

Let the number of children = C

A + C =292

4A + 1.5C = 888. solve for A, C

A = 292 - C

4[292 - C] + 1.5C = 888

1,168 - 4C + 1.5C = 888

-2.5C = - 280

C = -280 / -2.5

C = 112 - Number of children

292 - 112 = 180 - Number of adults

6 0
3 years ago
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