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navik [9.2K]
3 years ago
11

Which one of the following does not find the value of f ′(5) for f(x) = 3x2 – 2x – 4?

Mathematics
1 answer:
bixtya [17]3 years ago
5 0
The difference quotient is just the slope form, in a variation

so that should be (f(x+h)-f(x))/h as x approaches 0

the 2nd option is the differnce quotient, but with the negative distributed
the 3rd option is really f(x)-f(5) because f(5)=61 and that is valid
4th option is wrong because it is (f(x+h)+f(x))/h instead of (f(x+h)-f(x))/h


answer is 4th option
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What is the lateral area of a regular square pyramid if the base edges are of length 24 and perpendicular height is 5?
iren2701 [21]

Answer:

The lateral area is 624 unit²

Step-by-step explanation:

* Lets explain how to solve the problem

- The regular square pyramid has a square base and four congruent

 triangles

- The slant height of it = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}, where

  b is the length of its base and h is the perpendicular height

- Its lateral area = \frac{1}{2}.p.l, p is the perimeter of the base

 and l is the slant height

* Lets solve the problem

∵ The base of the pyramid is a square with side length 24 units

∵ Its perpendicular height is 5 units

∵ The slant height (l) = \sqrt{(\frac{1}{2}b)^{2}+h^{2}}

∴ l = The slant height of it = \sqrt{(\frac{1}{2}.24)^{2}+5^{2}}

∴ l = \sqrt{(12)^{2}+25}=\sqrt{144+25}=\sqrt{169}=13

∴ l = 13 units

∵ Perimeter of the square = b × 4

∴ The perimeter of the base (p) = 24 × 4 = 96 units

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∴ The lateral area = 624 unit²

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4 0
3 years ago
Can someone help me with these 2?
lesya [120]

answer: 1 over 165 step by step: #1 Evaluate the power 5 to the power of 1= 5 because any expression raised to the power of 1 if u asking what's is an expression the expression is five and together is 5 to the power of 1) #2 if a term like five doesn't have a exponent the exponent is 1) #3 remove the parathesis ) #4 subtract 1 and -2 u get 1 over 5 to the power of -4 and 5 to the power of negative four is 1 over 165) the second I don't know

6 0
4 years ago
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