If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper
Answer: We are given there are 49 cars
Also these 49 cars are in a line stretched 528 feet.
Now the average length of the car is:
Average length = 
=
Therefore, the average length of car is 10.78 feet
Well if it is a number like .933333333 you will have to round it, So now it is .93 and .93 in a fraction is 93/100
The answer is B f(x)= -3(x+1)^2+2
I’m pretty sure This rounds to 900
Answer:
Step-by-step explanation:
See the attachment for the chart