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Alinara [238K]
3 years ago
12

Which of the following is an example in which you are traveling at constant speed but not at constant velocity?

Physics
1 answer:
grin007 [14]3 years ago
3 0

Answer:

c) Driving around in a circle at exactly 100 km/hr.

This examples represents constant speed but not constant velocity.

Explanation:

To answer this question it is importan to know the difference between the concept of speed and velocity.

speed: Is the ratio of change in the displacement per unit of time. JUST  A MAGNITUDE

velocity: Is the ratio of change in the displacement per unit of time in a given direction. It is a composed value by magnitude and direction, this is know as a VECTOR.

So, in conclusion the speed is the magnitude or the scalar value, for the velocity vector.

In the example,

in a) Rolling freely down a hill in a cart, traveling in a straight line. <em>There is a component of acceleration, from earth gravity, so the speed is changing.</em>

<em />

in b) Driving backward at exactly 50 km/hr. <em> The direction and speed are the same, so speed and velocity are constant</em>.

In d) Jumping up and down, with a period of exactly 60 hops per minute. <em>There are changes in the speed, due to the acceleration and decceleration between the changes in the direction. Actually you have to stop to change direction between the ups and downs in the jumps. Also there is the gravitational component, always changing the speed.</em>

In c) Driving around in a circle at exactly 100 km/hr. <em>In this case the speed remains constant, while the direction is changing all the time.</em>

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Sergeu [11.5K]

Answer:

I think it is better if you read and shortly write my explanation

Explanation:

simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy.

8 0
3 years ago
A charge of 8.4*10^-4 moves at an angle of 35 degrees to a magnetic field that has a field strentgh of 6.7
12345 [234]

The force on a charged particle in a magnetic field is given by

the speed of the charged particle = 10842 m/s.

Explanation:

F= q V B sinθ

F=force=3.5 x 10⁻²N

q= charge= 8.4 x 10⁻⁴ C

B= magnetic field= 6.7 x 10⁻³ T

θ=35⁰

Thus the velocity is given by V=\frac{F}{q B sin35}

V=(3.5 x 10⁻²)/[(8.4 x 10⁻⁴)(6.7 x 10⁻³)(sin35)]

V=10842 m/s

3 0
3 years ago
A parallel beam of light in air makes an angle of 43.5 ∘ with the surface of a glass plate having a refractive index of 1.68. Yo
aniked [119]

Answer:

a) 46.5º  b) 64.4º

Explanation:

To solve this problem we will use the laws of geometric optics

a) For this part we will use the law of reflection that states that the reflected and incident angle are equal

     θ = 43.5º

This angle measured from the surface is

     θ_r = 90 -43.5

     θ_s = 46.5º

b) In this part the law of refraction must be used

     n₁ sin θ₁ = n₂. Sin θ₂

     sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

     θ_s = 90 - θ

     θ_s = 90- 43.5

     θ_s = 46.5º

     sin θ₂ = 1 / 1.68  sin 46.5

     sin θ₂ = 0.4318

     θ₂ = 25.6º

The angle with respect to the surface is

     θ₂_s = 90 - 25.6

     θ₂_s = 64.4º

measured in the fourth quadrant

3 0
3 years ago
I need help with question 4 please​
Yuki888 [10]

Answer:

V = 10 km / 1 hr = 10 km/hr

V = -10 j km / hr   if one were to use i, j, k as unit vectors with the usual orientation

4 0
3 years ago
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