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3 years ago

14

2. An egg rolls off the kitchen counter with a velocity of 4m/s. If

1 answer:

-Dominant- [34]3 years ago

6 0

Answer:

800m/s

Explanation:

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Do we include signs if we calculate Electric field strength?

expeople1 [14]

Yes because if not people wouldn't understand how did you calculate electric field strength.

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3 years ago

A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to res

Natalija [7]

Answer:

The time constant is $\tau = 17.5 \ s$

Explanation:

From the question we are told that

The spring constant is $k = 11.5 \ N/m$

The mass of the ball is $m_b = 490 \ g = 0.49 \ kg$

The amplitude of the oscillation t the beginning is $x = 6.70 cm = 0.067 \ m$

The amplitude after time t is $x_t = 2.20 cm = 0.022 \ m$

The number of oscillation is $N = 30$

Generally the time taken to attain the second amplitude is mathematically represented as

$t = N * T$ Here T is the period of oscillation

$t = N * 2\pi \sqrt{\frac{m}{k} }$

=> $t = 30 * 2 * 3.142 * \sqrt{\frac{ 0.490}{11.5} }$

=> $t = 38.88 \ s$

Generally the amplitude at time t is mathematically represented as

$x(t) = x e^{-\frac{at}{2m} }$

Here a is the damping constant so

at $t = 38.88 \ s$ , $x_t = 2.20 cm = 0.022 \ m$

So

$0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }$

=> $0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }$

taking natural log of both sides

=> $ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }$

=> $a = 0.028$

Generally the time constant is mathematically represented as

$\tau = \frac{m}{a}$

=> $\tau = \frac{0.490}{ 0.028}$

=> $\tau = 17.5 \ s$

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3 years ago

Which of the following statements is true? A. X-rays have longer wavelengths than microwaves. B. Radio waves have shorter wavele

3241004551 [841]

D is correct, Gamma rays have the shortest wavelength.

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3 years ago

I need help with life a child is adopted and I’m a duck where is my left shoe

Pavel [41]

just swim In water and find your shoe

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3 years ago

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g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin

Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

$i.e Normal \ Force(N) = mg cos \theta$

And $\theta = 90$ so

$N = 0$

c

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position

d

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work

Explanation:

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3 years ago

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