Answer:
153.9 g/mol
Explanation:
The freezing point depression for an ideal solution is given by the expresion:
ΔTf = Kf m
where:
ΔTf is the freezing point depression
Kf is the freezing constant of the solvent
m is the molalility which mol of solute per kilogram solvent
The moles of solute is the mass divided into its molecular weight, MW
substituting into the equation, we have:
4.49 º C = 6.91 ºC/m x [(1.0 g/MW) / 0.010 kg]
4.49 º C = 6.91 ºC/mol/kg x [(1.0 g/MW) / 0.010 kg]
⇒4.49 = 691 g/mol/MW
⇒ MW = 691 / 4.49 g/mol = 153.9 g /mol
Answer:
507599.78 J
Explanation:
Charge input = current x time
=15 x 53 x 60
= 47000 coulomb
increase in voltage
= 12.6 - 9 = 3.6
capacity of the battery C = Charge input / increase in voltage
= 47000 / 3.6 = 13055.55
energy of the capacitor = 1/2 CV²
Initial energy of car battery = .5 x 13055.55 x 9 x 9
= 528749.77 J
Final energy of car battery
= .5 x 13055.55 x 12.6 x 12.6
= 1036349.55
Increase in energy = 507599.78 J
Answer:
Hey! Your answer -:
P.E = Mgh
= 35*9.8*1.5
= 514.5
So, pe of ur dog is 514.5
Hope it helps!
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