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3 years ago

the area of aron's favorite poster is 6 square feet. the length of the poster is 3 feet. find the width of the poster

Mathematics

2 answers:

MatroZZZ [7]3 years ago

6 0

Answer:

The width is 2 ft

Step-by-step explanation:

We know the area of a rectangle is

A = l*w

The area is 6 and the length is 3

6 = 3*w

Divide each side by 3

6/3 = 3w/3

2 =w

The width is 2 ft

mash [69]3 years ago

3 0

Answer:

Step-by-step explanation:

Well let's see.... 6/3=2. To check your work simply measure 2x3 and you get 6.

The reason this is: Due to Aarons poster being 6 square feet, the length is 3 and the only other least common multiple for 6 besides 1 and itself and 3 would be 2, leaving that to be your final answer.

BTW: This is a formula, which can work for either Area or Volume.

Hope this helped,

OhBryce

PS. Brainly Please???

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Base: z(x)=cosx Period:180 Maximum:5 Minimum: -4 What are the transformation? Domain and Range? Graph?

garik1379 [7]

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is $z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$ .

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be $z (x) = \cos x$ the base formula, where $x$ is measured in sexagesimal degrees. This expression must be transformed by using the following data:

$T = 180^{\circ}$ (Period)

$z_{min} = -4$ (Minimum)

$z_{max} = 5$ (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of $2\pi$ radians. In addition, the following considerations must be taken into account for transformations:

1) $x$ must be replaced by $\frac{2\pi\cdot x}{180^{\circ}}$ . (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

$\Delta z = \frac{z_{max}-z_{min}}{2}$

$\Delta z = \frac{5+4}{2}$

$\Delta z = \frac{9}{2}$

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

$z_{m} = \frac{z_{min}+z_{max}}{2}$

$z_{m} = \frac{1}{2}$

The new function is:

$z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)$

Given that $z_{m} = \frac{1}{2}$ , $\Delta z = \frac{9}{2}$ and $T = 180^{\circ}$ , the outcome is:

$z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)$

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

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3 years ago

The lengths of a lawn mower part are approximately normally distributed with a given mean mc021-1.jpg = 4 in. and standard devia

Aleonysh [2.5K]

<span>The best answer that is given to the question that is being presented above would be 68%. Since it is normally distributed and the lengths' range fall between the first lower and upper standard deviations of the distribution (which is 68%), then the answer is 68%. </span>

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3 years ago

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Help I'm really stuck!!!

faust18 [17]

399.6 square meters
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3 years ago

Can i get help plzz .....

wel

Answer:

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Step-by-step explanation:

If you already spent $5 then you have $6 remaining so you will just divide 6 and 20 and you will get 0.3 so $0.30

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3 years ago

the area of aron's favorite poster is 6 square feet. the length of the poster is 3 feet. find the width of the poster​

the area of aron's favorite poster is 6 square feet. the length of the poster is 3 feet. find the width of the poster