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3 years ago

Someone help me . I don’t know the answer!!

Mathematics

1 answer:

ollegr [7]3 years ago

5 0

Answer:

the answer is x=8, y=7

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Studentka2010 [4]

Answer:

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2 years ago

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PLEASE HELP!!!!! Florian ran 1.2 miles and walked 4.8 laps around the path at the park for a total distance of 3.6 miles. Which

fgiga [73]

Answer:

The correct answer would be D) 4.8x + 1.2 = 3.6; x = 0.5 mile

Step-by-step explanation:

This is because laps would be the dependent variable, so we know the number of them (4.8) would be multiplied by the variable (x). We also know that 1.2 is the constant. Now we can solve to make sure this is the right equation.

4.8x + 1.2 = 3.6

4.8x = 2.4

x = 0.5

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3 years ago

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How many gallons are in 1,980 milliliters? Rounded to the nearest hundredth

Setler [38]

I believe this is the answer? If not I am sorry!

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2 years ago

Can u please do 1,2

Sidana [21]

1) First, you have to add all the 3 pieces of wood
10+7.5+12= 29.5 ft.
Second, you have to add the pieces that he has used
5.2 +6.2= 11.4 ft
Third, you have subtract the used wood from the whole wood to get how many feet he didn't use
29.5 - 11.4=18.1 ft.
I hope it helped. But, sorry don't know how to do number 2.

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2 years ago

Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

Child 1 final position => $x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t$
Child 2 final position => $x_{2f} =0+v_{2} t$

4) Sum the equations and equate to 3

$x_{1f} +x_{2f} =3$

5) Substitute the values we already know

$1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]$

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

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2 years ago