Answer:
<u>2 </u>sack of cement is required to cover Joel's entire floor.
Step-by-step explanation:
Given:
A sack cement can cover area = 45 sq. ft
Length of Joel floor = 8 ft
Width of Joel Floor = 7 ft
We will first find the Area of Joel's Floor
Area is the Product of length and width.
Area of the Floor = ![length \times width](https://tex.z-dn.net/?f=length%20%5Ctimes%20width)
Substituting the values we get;
Area of the Floor = ![8\times 7 = 56\ ft^2](https://tex.z-dn.net/?f=8%5Ctimes%207%20%3D%2056%5C%20ft%5E2)
Now Given:
1 sack of cement cover area = 45 sq ft
Number of sack cement required to cover area = 56 sq. ft.
By Using Unitary method we will find the same.
∴ Number of sack cement required = ![\frac{56}{45} = 1.24](https://tex.z-dn.net/?f=%5Cfrac%7B56%7D%7B45%7D%20%3D%201.24)
Since Sack of cement cannot be in point value hence we can say 2 sack cement is required.
Hence we can say 2 sack of cement is required to cover Joel's entire floor.
9,000,000
-2,000,000 (1,000,000 for each of the numbers taken out except 0, a number 7,000,000 can't start with 0 unless it is 0 or a decimal.)
The sum of x and y decreased by their product...
(x + y) - xy <== ur expression
Answer:
x<-3
Step-by-step explanation: