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Murljashka [212]
3 years ago
10

In a race, Car #1 went an average of

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
I think the mile is 10 miles per hour
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Find the volume of the given solid: Bounded by the cylinder y^2+z^2=4 and the planes x = 2y, x = 0, z = 0 in the first octant.
rodikova [14]

The solution would be like this for this specific problem:

<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫ 0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [ -2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [ 2·r² ] dr </span>
<span>= (2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>

So the volume of the given solid is 16/3. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0
3 years ago
What is the result when x^3-2x^2+5x-13x 3 −2x 2 +5x−13 is divided by x-2x−2?
Aleksandr [31]

yo k se wey: rg`weaofjwafgEWF3WRF1QTFG3Q2TGF2

3 0
3 years ago
What is 6^-2/2^4 ???????????????​
sergij07 [2.7K]

Answer:

1/52

Step-by-step explanation:

2 to the fourth is 16, and 6 to the second is 36. However, since it's a negative exponent, you'd have to move it down to to the bottom of the fraction, creating 1/16+36, which makes 1/52.

7 0
3 years ago
Estimate the answer to 65.78 + 13.43 by first rounding each number to the nearest tenth.
gizmo_the_mogwai [7]
65.8 + 13.4 =  79 .2. So the answer is c 
6 0
3 years ago
Suppose that we have collected a sample of 8 observations with values 12.6, 12.9, 13.4, 12.3, 13.6, 13.5, 12.6, and 13.1. What a
Korolek [52]

Answer:

The sample mean is 13.

The sample variance is 0.2286.

The sample standard deviation is 0.4781.

Step-by-step explanation:

The sample is:

S = {12.6, 12.9, 13.4, 12.3, 13.6, 13.5, 12.6, 13.1}

The sample is of size <em>n</em> = 8.

The formula to compute the sample mean, sample variance and sample standard deviation are:

\bar x=\frac{1}{n} \sum x

s^{2}=\frac{1}{n}\sum (x-\bar x)^{2} \\s=\sqrt{\frac{1}{n}\sum (x-\bar x)^{2} }\\

Compute the sample mean as follows:

\bar x=\frac{1}{n} \sum x\\=\frac{1}{8}(12.6+ 12.9+ 13.4+ 12.3+ 13.6+ 13.5+ 12.6+ 13.1)\\=\frac{104}{8}\\ =13

The sample mean is 13.

Compute the sample variance as follows:

s^{2}=\frac{1}{n-1}\sum (x-\bar x)^{2} \\=\frac{1}{8-1}[(12.6-13)^{2}+(12.9-13)^{2}+(13.4-13)^{2}+...+(13.1-13)^{2}] \\=\frac{1}{7}\times1.6\\=0.2286

The sample variance is 0.2286.

Compute the sample standard deviation as follows:

s=\sqrt{s^{2}}\\=\sqrt{0.2286}\\=0.4781

The sample standard deviation is 0.4781.

4 0
3 years ago
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