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Dmitrij [34]
4 years ago
7

Which fraction represents the decimal 0. ModifyingAbove 1 2 with Bar?

Mathematics
2 answers:
Licemer1 [7]4 years ago
6 0

Answer:

\frac{3}{25}

Step-by-step explanation:

Given that \overline{0.12} is the repeating decimal.

The repeating decimal \overline{0.12} is converted into the fraction as :

\overline{0.12} = \frac{3}{x}

<=> 0.121212 = \frac{3}{x}

Multiplying both sides by x, we have,

<=> 0.121212x = 3

Dividing both sides by 0.121212, we get:

<=> x = \frac{3}{0.121212}

<=> x = 25

So the  fraction represents the decimal \overline{0.12} is: \frac{3}{25}

Hope it well find you well.

yaroslaw [1]4 years ago
3 0

Answer:

C.) 4/33

Step-by-step explanation:

Took the test on ed.

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Answer:

Could you specify what other answers there are in order for me to answer this?

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3 years ago
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What is:6(x+4)=30<br> With working out please
stepladder [879]

Answer:

x=1

Step-by-step explanation:

6(x+4)=30

1) Distribute 6 to x and 4:

6x+24=30

2) Subtract 24 from both sides:

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3) Divide both sides by 6:

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7 0
3 years ago
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Need it solved correctly for khan academy
RUDIKE [14]

The tiger population loses 3/5 of its size every 2.94 decades

<h3>Rate of change using differential calculus</h3>

The given equation is:

N(t)=710(\frac{8}{125} )^t

Find the derivative of the given function

\frac{dN}{dt} =710(0.064)^tln(0.064)\\\\\frac{dN}{dt} =-1951.7(0.064)^t

When the tiger loses 3/5 of its population

dN/dt = 3/5

Solve for t

\frac{3}{5} =-1951.7(0.064)^t\\\\-0.0003=(0.064)^t

Take the natural logarithm of both sides

ln(-0.0003)=t(ln0.064)\\\\-8.087=-2.75t\\\\t=\frac{-8.087}{-2.75} \\\\t=2.94

The tiger population loses 3/5 of its size every 2.94 decades

Learn more on rate of change using calculus here: brainly.com/question/96116

#SPJ1

6 0
2 years ago
Find the general solution to the differential equation modeling how a person learns:
Luda [366]

Here we want to solve differential equations, we will see that the general solution is:

y = A*e^{-t} + 100

We want to solve the differential equation:

\frac{dy}{dt}  = 100 - y

From this is pretty clear that y is an exponential function, with an exponent of -1*t.

We can write it generally as:

y = A*e^{-t} + B\\\\\frac{dy}{dt}  = -A*e^{-t}

Then if we set B = 100 we get:

y = A*e^{-t} + 100\\\\\frac{dy}{dt}  = -A*e^{-t} \\\\\frac{dy}{dt}  = -A*e^{-t} - 100 + 100 = -y + 100

So we just found the general form of the function.

Now we have two cases:

A) y(0) = 35

y(0) = A*e^{-0} + 100  = 35\\=  A + 100 = 35\\\\A = 35 - 100 = -65

In this case, the function is:

y = -65*e^{-t} + 100

B) y(0) = 125

125 = A*e^0 + 100\\\\\125 - 100 = A\\\\25 = A

In this case, the function is:

y = 25*e^{-t} + 100

Now we want to see which one of the two can represent how a person learns. Just look at the graph below:

The green line is the one for y(0) = 35, and the blue one is for y(0) = 125.

Notice that for small values of t, the blue function is really large, thus it can't really model how a person learns (is larger for smaller values of t than for larger values).

So y(0) = 35 represents better how a <em>person can learn</em> (but not exactly, because you can see that it eventually becomes almost constant, which is something that really does not happen) so the correct option is <u>D: none of the above.</u>

If you want to learn more, you can read:

brainly.com/question/353770

3 0
3 years ago
9341/2 scientific notation
Darya [45]
Answer: 9.34 x 10^3
Hope this helps
5 0
4 years ago
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