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podryga [215]
3 years ago
8

Ten pairs of data yield r = 0.003 and the regression equation =2+3x Also, the mean = 5 What is the best predicted value of y for

x = 2?A. 7.0 B. 5.0 C. 8.0 D. 17.0
Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

\hat y(2)=2 +3(2) =8

C 8.0

Step-by-step explanation:

Assuming the linear model y=mx+b where m is the slope and b the intercept.

For this case the slope with the following formula:

m=\frac{S_{xy}}{S_{xx}}

Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

b=\bar y -m \bar x

After the calculations we see that m=3 and b=2 from the info given by the linear model.

For this case we have the equation obtained by least squares given by:

\hat y =2 +3x

Where 2 represent the intercept and 3 the slope. We are interested on the best predicted value of y when x=2.

If we see our linear model we have the equation in terms of y and x. So we can replace directly the value of x=2 into the equation and see what we got:

\hat y(2)=2 +3(2) =8

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Answer:

A = 14 m^2

Step-by-step explanation:

The area of a trapezoid is found by

A = 1/2 (b1+b2) *h  where b is the length of the bases and h is the height

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3 years ago
85% of what number is 10.2
Free_Kalibri [48]

<em>Answer:</em>

<em>n = 12</em>

<em>Step-by-step explanation:</em>

<em>85%×n = 10.2</em>

<em>85n/100 = 10.2</em>

<em>85n = 1020</em>

<em>n = 1020 : 85</em>

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Need help finding n forgot how to do this
andreyandreev [35.5K]

Answer:

n  =                                    3\sqrt{2}

There are two best ways to solve this.

using cosine method:

cos(n) =  \frac{adjacent}{hypotenuse}

cos(60) = \frac{adjacent}{6\sqrt{2} }

adjacent,n = cos(60) * 6\sqrt{2}

n  =                                    3\sqrt{2}

using sine method:

sin(n) = \frac{opposite}{hypotenuse}

sin(30)=  \frac{n}{6\sqrt{2} }

n  = sin(30) * 6\sqrt{2}

n = 3\sqrt{2}

There are many ways, not to make it complex, these are the best ways to solve for n. Hope it helps ~

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