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zzz [600]
3 years ago
14

3 Times minus 16=14math

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0
3x-16=14

14+16=30

3x=30

30 divided by 3 equals 10

x = 10
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EXERC
eimsori [14]

Answer:551.3212cm³

Step-by-step explanation:

Find the image attached

The volume is made up of a cone, cylinder and a hemisphere

Volume of the shape = Volume of cone + volume of cylinder + volume of hemisphere

Get the volume of the cone;

Volume of a cone Vc = 1/3πr²h

r is the base radius = 3.5cm

Height = 10cm

Vc = 1/3π(3.5)²(6)

Vc = 1/3π(12.25)(6)

Vc = 12.25 * 2π

Vc = 24.5π cm³

Get the volume of the cylinder;

Vcy = πr²h

r = 3.5cm

h = 10cm

Vcy = π(3.5)²(10)

Vcy = π(12.25)(10)

Vcy = π(122.5)

Vcy = 122.5π cm³

Get rhe volume of the hemisphere;

Volume of hemisphere = 2/3 πr³

r = 3.5cm

Vh =  2/3 π(3.5)³

Vh = 2/3π(42.875)

Vh = 28.58π cm³

Volume of the shape = VC + Vcy + Vh

Volume of the shape = 24.5π+122.5π+28.58π

Volume of the shape = 175.58π

<em>Volume of the shape = 551.3212cm³</em>

7 0
3 years ago
-15= z/-2 answer please?​
faust18 [17]

Answer:

30

Step-by-step explanation:

-15=\frac{z}{-2}\\\\(-15)(-2)=z\\\\30=z

4 0
3 years ago
What non-zero rational number must be placed in the square so that the simplified product of these two binomials is a binomial:
aleksandrvk [35]

The product would expand to

(7t-10)(5t+x)=35t^2+7tx-50t-10x=35t^2+(7x-50)t-10x

This is a trinomial, and the only way to make it a binomial is to cancel out a coefficient using our variable x.

So, we can cancel either the linear term or the constant term.

In the first case, we require

7x-50=0 \iff 7x=50 \iff x=\dfrac{50}{7}=\dfrac{49}{7}+\dfrac{1}{7}=7\dfrac{1}{7}

In the second case, we require

-10x=0\iff 10x=0 \iff x=0

But x must be a non-zero rational number, so this solution is not feasible.

7 0
3 years ago
Read 2 more answers
Is AB a tangent why or why not??​
Minchanka [31]

Answer:

As angle B is a right triangle, the sides AB and CB are perpendicular to each other. From the property of all tangents to a circle given in the beginning it can be concluded that AB is a tangent of the circle

5 0
3 years ago
Please help! Freshman in high-school Algebra 1​
Liono4ka [1.6K]

Answer:

ighs ths fnflsna

Step-by-step explanation:

dihfujsnfgsdf g

4 0
3 years ago
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