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2 years ago

14

GEOMETRY PROOFS!

2 answers:

yarga [219]2 years ago

4 0

From the given figure ,

RECA is a quadrilateral

RC divides it into two parts

From the triangles , ∆REC and ∆RAC

RE = RA (Given)

angle CRE = angle CRA (Given)

RC = RC (Common side)

Therefore, ∆REC is Congruent to ∆RAC

∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

<em>Additional</em><em> comment</em><em>:</em><em>-</em>

SAS property:-

"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)

<u>also</u><u> </u><u>read</u><u> </u><u>similar</u><u> questions</u><u>:</u> Complete this proof. Given: EC AC, DB AC, ∠A = ∠F Prove: ΔMDF ∼ ΔNCA..

brainly.com/question/16250124?referrer

Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...

brainly.com/question/11763540?referrer

blsea [12.9K]2 years ago

3 0

Step-by-step explanation:

<u>Given:</u>

RA ≅ RE
EC ≅ AC

<u>Also we observe that:</u>

RC ≅ CR as common side of both triangles

<u>Since three sides of ΔREC and ΔRAC are congruent:</u>

ΔREC ≅ ΔRAC by SSS

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